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Exponential equations and inequalities
$ 6^{1+x}+6^{1+x}=12 $
$3^{x+1}-3^x=3^x+9$
$ \frac13(108−3^x)=3^x $
$ 10^x+100=10 $
$ 3^{2x}-12\cdot 3^x+27=0 $
Solutions to Exponential Inequalities
Submitted by
michaela.bailova
on Fri, 04/05/2024 - 13:19
$ (0{.}25)^{2x-1} \leq 16 $
Solutions of Exponential Equations
Submitted by
michaela.bailova
on Tue, 02/06/2024 - 15:13
$\left(\frac{1}{2}\right)^{x-1} < \frac{1}{2}$
$2^{-x}=8$
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