Equations and inequalities with parameters

9000375405

Level: 
A
Find a set of the values of the real parameter \(a\) which ensure that the following equation has a unique solution. \[ a^{2}x + 6x = a + 1 - 5ax \]
\(\mathbb{R}\setminus \left \{-3;-2\right \}\)
\(\mathbb{R}\setminus \left \{2;3\right \}\)
\(\mathbb{R}\setminus \left \{-1;2;3\right \}\)
\(\mathbb{R}\setminus \left \{-3;-2;1\right \}\)

9000140001

Level: 
C
Consider the equation \[ \frac{4a} {x} - \frac{1} {ax} + \frac{2} {a} = 4 \] with unknown \(x\) and a parameter \(a\in \mathbb{R}\setminus \{0\}\). Identify a true statement.
If \(a = \frac{1} {2}\), then the solution is \(x\in \mathbb{R}\setminus \{0\}\).
If \(a = \frac{1} {2}\), then the equation has no solution.
If \(a = \frac{1} {2}\), then the solution is \(x\in \mathbb{R}\).

9000140002

Level: 
A
Solve the following equation with unknown \(x\) and a real parameter \(a\in\mathbb{R}\setminus\{0\}\). \[ \frac{x+a} {a} = ax - 1\]
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a\in\{-1;1\} & \emptyset \\ a\notin\{-1;0;1\} & \left\{\frac{2a}{(a-1)(a+1)}\right\} \\\hline \end{array}\)
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a=-1 & \emptyset \\ a\notin\{-1;0\} & \left\{\frac{2a}{(a-1)(a+1)}\right\} \\\hline \end{array}\)
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a\in\{-1;1\} & \mathbb{R} \\ a\notin\{-1;0;1\} & \left\{\frac{2a}{(a-1)(a+1)}\right\} \\\hline \end{array}\)

9000140003

Level: 
A
Solve the following equation with unknown \(x\) and a real parameter \(a\in\mathbb{R}\setminus\{0\}\). \[ax - \frac{2} {a^{2}} = \frac{4x+1} {a} \]
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a=-2 & \mathbb{R} \\ a=2 & \emptyset \\ a\notin\{-2;0;2\} & \left\{\frac1{a(a-2)}\right\} \\\hline \end{array}\)
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a=-2 & \mathbb{R}\setminus\{1\} \\ a=2 & \emptyset \\ a\notin\{-2;0;2\} & \left\{\frac1{a(a-2)}\right\} \\\hline \end{array}\)
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a=-2 & \emptyset \\ a=2 & \mathbb{R} \\ a\notin\{-2;0;2\} & \left\{\frac1{a(a-2)}\right\} \\\hline \end{array}\)

9000140004

Level: 
C
Solve the following equation with unknown \(x\) and a real parameter \(a\in\mathbb{R}\). \[ \frac{a^{2}(x-1)} {ax-3} = 3 \]
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a=0 & \emptyset \\ a=3 & \mathbb{R}\setminus\{1\} \\ a\notin\{0;3\} & \left\{\frac{a+3}a\right\} \\ \hline \end{array}\)
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a=0 & \emptyset \\ a=3 & \{1\} \\ a\notin\{0;3\} & \left\{\frac{a+3}a\right\} \\ \hline \end{array}\)
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a\in\{0;3\} & \emptyset \\ a\notin\{0;3\} & \left\{\frac{a+3}a\right\} \\ \hline \end{array}\)
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a=0 & \emptyset \\ a=3 & \mathbb{R} \\ a\notin\{0;3\} & \left\{\frac{a+3}a\right\} \\ \hline \end{array}\)

9000140005

Level: 
C
Solve the following equation with unknown \(x\) and a real parameter \(a\in\mathbb{R}\setminus\{0\}\). \[\frac ax-\frac4{ax}=1-\frac2a\]
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a=-2 & \emptyset \\ a=2 & \mathbb{R}\setminus\{0\} \\ a\notin\{-2;0;2\} & \left\{a+2\right\} \\ \hline \end{array}\)
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a=2 & \mathbb{R}\setminus\{0\} \\ a\notin\{0;2\} & \left\{a+2\right\} \\ \hline \end{array}\)
\( \begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a=2 & \mathbb{R} \\ a\notin\{0;2\} & \left\{a+2\right\} \\ \hline \end{array}\)
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a=2 & \mathbb{R}\setminus\{1\} \\ a\notin\{0;2\} & \left\{a+2\right\} \\ \hline \end{array}\)

9000104502

Level: 
A
Solve the following equation with unknown \(x\) and a real parameter \(a\in\mathbb{R}\setminus\{-1\}\). \[\frac{x} {a+1} = x - a\]
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a=0 & \mathbb{R} \\ a\notin\{-1;0\} & \{a+1\} \\\hline \end{array}\)
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a=0 & \mathbb{R} \\ a\notin\{-1;0\} & \emptyset \\\hline \end{array}\)
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a=0 & \emptyset \\ a\notin\{-1;0\} & \{a+1\} \\\hline \end{array}\)