9000140002 Level: ASolve the following equation with unknown x and a real parameter a∈R∖{0}. x+aa=ax−1ParameterSolution seta∈{−1;1}∅a∉{−1;0;1}{2a(a−1)(a+1)}ParameterSolution seta=−1∅a∉{−1;0}{2a(a−1)(a+1)}ParameterSolution seta∈{−1;1}Ra∉{−1;0;1}{2a(a−1)(a+1)}
9000140003 Level: ASolve the following equation with unknown x and a real parameter a∈R∖{0}. ax−2a2=4x+1aParameterSolution seta=−2Ra=2∅a∉{−2;0;2}{1a(a−2)}ParameterSolution seta=−2R∖{1}a=2∅a∉{−2;0;2}{1a(a−2)}ParameterSolution seta=−2∅a=2Ra∉{−2;0;2}{1a(a−2)}
9000140004 Level: CSolve the following equation with unknown x and a real parameter a∈R. a2(x−1)ax−3=3ParameterSolution seta=0∅a=3R∖{1}a∉{0;3}{a+3a}ParameterSolution seta=0∅a=3{1}a∉{0;3}{a+3a}ParameterSolution seta∈{0;3}∅a∉{0;3}{a+3a}ParameterSolution seta=0∅a=3Ra∉{0;3}{a+3a}
9000140005 Level: CSolve the following equation with unknown x and a real parameter a∈R∖{0}. ax−4ax=1−2aParameterSolution seta=−2∅a=2R∖{0}a∉{−2;0;2}{a+2}ParameterSolution seta=2R∖{0}a∉{0;2}{a+2}ParameterSolution seta=2Ra∉{0;2}{a+2}ParameterSolution seta=2R∖{1}a∉{0;2}{a+2}
9000104310 Level: BAssuming a∈(0;1), solve the following inequality. 2a(1−a)x>3(32a(1−a);∞)(−32a(1−a);∞)(−32a(1−a);32a(1−a))(−∞;32a(1−a))
9000104402 Level: AFind a set of the values of the real parameter a which ensure that the following equation has no solution. 2a2x−ax−2a=−1{0}{12}{−12}{−12;12}
9000104403 Level: AFind a set of the values of the real parameter a which ensure that the following equation has infinitely many solutions. 3a2x−2ax+4=6a{23}{−23}{0}{0;23}
9000104404 Level: AFind a set of the values of the real parameter a which ensure that the following equation has infinitely many solutions. a2x+1=a2+ax{1}{−1;1}{0}{−1}
9000104405 Level: AFind a set of the values of the real parameter a which ensure that the following equation has a unique solution. a3x+3=3a2x+aR∖{0;3}{0}{0;3}R∖{3}
9000104501 Level: AConsider equation x−3a=a−x3+2 with an unknown x∈R and a real parameter a∈R∖{0}. Identify a statement which is not true.For a∈{−3;0} we have x=1a+3.For a∉{−3;0} we have x=a+3.If a=−3, then the equation has infinitely many solutions.