9000140002 | math4u.vsb.cz

SubArea:

Equations and inequalities with parameters

Level:

Project ID:

9000140002

Accepted:

1

Clonable:

0

Easy:

0

Solve the following equation with unknown

x

and a real parameter

a \in R ∖ {0}

.

\frac{x + a}{a} = a x - 1

\begin{array}{cc} Parameter & Solution set \\ a \in {- 1; 1} & \emptyset \\ a \notin {- 1; 0; 1} & {\frac{2 a}{(a - 1) (a + 1)}} \end{array}

\begin{array}{cc} Parameter & Solution set \\ a = - 1 & \emptyset \\ a \notin {- 1; 0} & {\frac{2 a}{(a - 1) (a + 1)}} \end{array}

\begin{array}{cc} Parameter & Solution set \\ a \in {- 1; 1} & R \\ a \notin {- 1; 0; 1} & {\frac{2 a}{(a - 1) (a + 1)}} \end{array}