Equations and Inequalities with Parameters

9000104503

Level: 
C
Solve the following equation with unknown \(x\) and a real parameter \(a\in\mathbb{R}\). \[\frac{a^{2}(x-1)} {ax-2} = 2\]
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a=0 & \emptyset \\ a=2 & \mathbb{R}\setminus\{1\} \\ a\notin\{0,2\} & \left\lbrace\frac{a+2}a\right\rbrace \\\hline \end{array}\)
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a\in\{0,2\} & \mathbb{R} \\ a\notin\{0,2\} & \left\{\frac{a+2}a\right\} \\\hline \end{array}\)
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a=0 & \emptyset \\ a=2 & \mathbb{R} \\ a\notin\{0,2\} & \left\lbrace\frac{a+2}a\right\rbrace \\\hline \end{array}\)
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a=0 & \mathbb{R}\setminus\{1\} \\ a=2 & \emptyset \\ a\notin\{0,2\} & \left\lbrace\frac{a+2}a\right\rbrace \\\hline \end{array}\)

9000104504

Level: 
C
Solve the following equation with unknown \(x\) and a real parameter \(a\in\mathbb{R}\setminus\{0\}\). \[\frac{1} {x-a} + 1 = \frac{1} {a}\]
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a=1 & \emptyset \\ a\notin\{0,1\} & \left\lbrace\frac{a(a-2)}{a-1}\right\rbrace \\\hline \end{array}\)
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a=1 & \mathbb{R}\setminus\{1\} \\ a\notin\{0,1\} & \left\lbrace\frac{a(a-2)}{a-1}\right\rbrace \\\hline \end{array}\)
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a=1 & \mathbb{R} \\ a\notin\{0,1\} & \left\lbrace\frac{a(a-2)}{a-1}\right\rbrace \\\hline \end{array}\)

9000104505

Level: 
A
Solve the following equation with unknown \(x\) and a real parameter \(a\in\mathbb{R}\setminus\{-3,3\}\). \[\frac{a-x} {a-3} - \frac{6a} {a^{2}-9} = \frac{x-3} {a+3} \]
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a=0 & \emptyset \\ a\notin\{-3,0,3\} & \left\lbrace\frac{a^2-9}{2a}\right\rbrace \\\hline \end{array}\)
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a=0 & \mathbb{R} \\ a\notin\{-3,0,3\} & \left\lbrace\frac{a^2-9}{2a}\right\rbrace \\\hline \end{array}\)
\(\begin{array}{cc} \hline \text{Parameter} & \text{Solution set}\\ \hline a=0 & \mathbb{R}\setminus\{0\} \\ a\notin\{-3,0,3\} & \left\lbrace\frac{a^2-9}{2a}\right\rbrace \\\hline \end{array}\)

9000034701

Level: 
B
Identify a set of the values of the real parameter \(m\) which ensure that the equation \[ \frac{m} {x} - 8 = \frac{1} {x} -\frac{m + 3} {2} \] has solution \(x = 2\).
\(\left \{7\right \}\)
\(\left \{10\right \}\)
\(\left \{6\right \}\)
\(\left \{\frac{5} {2}\right \}\)