Derivace funkce

9000070702

Část: 
B
Určete první derivaci funkce \(f\colon y = (x^{2} - 3x + 2)^{\frac{1} {2} }\).
\(f^{\prime}(x) = \frac{2x-3} {2\sqrt{x^{2 } -3x+2}};\ x\in \mathbb{R}\setminus \left \langle 1;2\right \rangle \)
\(f^{\prime}(x) = \frac{2x-3} {2\sqrt{x^{2 } -3x+2}};\ x\in \mathbb{R}\setminus \left (1;2\right )\)
\(f^{\prime}(x) = (4x - 6)\sqrt{x^{2 } - 3x + 2};\ x\in \mathbb{R}\setminus \left \langle 1;2\right \rangle \)
\(f^{\prime}(x) = (4x - 6)\sqrt{x^{2 } - 3x + 2};\ x\in \mathbb{R}\setminus \left (1;2\right )\)

9000070708

Část: 
B
Určete první derivaci funkce \(f\colon y =\ln \left (\frac{1+x} {1-x}\right )\).
\(f^{\prime}(x) = \frac{2} {1-x^{2}} ;\ x\in \left (-1;1\right )\)
\(f^{\prime}(x) = \frac{2} {1-x^{2}} ;\ x\in \mathbb{R}\setminus \left \{-1;1\right \}\)
\(f^{\prime}(x) = \frac{1-x} {1+x};\ x\in \left (-1;1\right )\)
\(f^{\prime}(x) = \frac{1-x} {1+x};\ x\in \mathbb{R}\setminus \left \{-1;1\right \}\)

9000070703

Část: 
B
Určete první derivaci funkce \(f\colon y = \sqrt{\sin x -\cos x}\).
\(f^{\prime}(x) = \frac{\sin x+\cos x} {2\sqrt{\sin x-\cos x}};\ x\in \left ( \frac{\pi }{4} + 2k\pi ; \frac{5\pi } {4} + 2k\pi \right ),\ k\in \mathbb{Z}\)
\(f^{\prime}(x) = \frac{\sin x+\cos x} {2\sqrt{\sin x-\cos x}};\ x\in \left \langle \frac{\pi }{4} + 2k\pi ; \frac{5\pi } {4} + 2k\pi \right \rangle ,\ k\in \mathbb{Z}\)
\(f^{\prime}(x) = \frac{\sin x-\cos x} {2\sqrt{\sin x-\cos x}};\ x\in \left \langle \frac{\pi }{4} + 2k\pi ; \frac{5\pi } {4} + 2k\pi \right \rangle ,\ k\in \mathbb{Z}\)
\(f^{\prime}(x) = \frac{\sin x-\cos x} {2\sqrt{\sin x-\cos x}};\ x\in \left ( \frac{\pi }{4} + 2k\pi ; \frac{5\pi } {4} + 2k\pi \right ),\ k\in \mathbb{Z}\)

9000070704

Část: 
B
Určete první derivaci funkce \(f\colon y = \frac{1} {\cos x+3x^{2}} \).
\(f^{\prime}(x) = \frac{\sin x-6x} {(3x^{2}+\cos x)^{2}} ;\ x\in \mathbb{R}\)
\(f^{\prime}(x) = \frac{6x-\sin x} {(3x^{2}+\cos x)^{2}} ;\ x\in \mathbb{R}\)
\(f^{\prime}(x) = \frac{\sin x-6x} {3x^{2}+\cos x};\ x\in \mathbb{R}\)
\(f^{\prime}(x) = \frac{6x-\sin x} {3x^{2}+\cos x};\ x\in \mathbb{R}\)

9000070706

Část: 
B
Určete první derivaci funkce \(f\colon y = \sqrt{x^{2 } + 3x}\).
\(f^{\prime}(x) = \frac{2x+3} {2\sqrt{x^{2 } +3x}};\ x\in \left (-\infty ;-3\right )\cup \left (0;\infty \right )\)
\(f^{\prime}(x) = \frac{2x+3} {2\sqrt{x^{2 } +3x}};\ x\in \left (-\infty ;-3\right \rangle \cup \left \langle 0;\infty \right )\)
\(f^{\prime}(x) = \frac{2x+3} {\sqrt{x^{2 } +3x}};\ x\in \left (-\infty ;-3\right )\cup \left (0;\infty \right )\)
\(f^{\prime}(x) = \frac{\sqrt{x^{2 } +3x}} {2x+3} ;\ x\in \left (-\infty ;-3\right \rangle \cup \left \langle 0;\infty \right )\)

9000063302

Část: 
B
Derivace funkce \(f\colon y = (3x^{2} + 2)^{3}\) je rovna:
\(f'(x) = 18x(3x^{2} + 2)^{2},\ x\in \mathbb{R}\)
\(f'(x) = 18x(3x^{2} + 2),\ x\in \mathbb{R}\)
\(f'(x) = 18x^{2}(3x + 2)^{2},\ x\in \mathbb{R}\)
\(f'(x) = 108x^{2},\ x\in \mathbb{R}\)

9000063303

Část: 
C
Derivace funkce \(f\colon y = \sqrt{\sin x}\) je rovna:
\(f'(x) = \frac{\cos x} {2\sqrt{\sin x}},\ x\in \mathop{\mathop{\bigcup }}\nolimits _{k\in \mathbb{Z}}\left (2k\pi ;\pi + 2k\pi \right )\)
\(f'(x) = \frac{\sin x} {2\sqrt{\cos x}},\ x\in \mathop{\mathop{\bigcup }}\nolimits _{k\in \mathbb{Z}}\left (2k\pi ; \frac{\pi } {2} + 2k\pi \right )\)
\(f'(x) = \frac{1} {2\sqrt{\sin x}},\ x\in \mathop{\mathop{\bigcup }}\nolimits _{k\in \mathbb{Z}}\left (2k\pi ;\pi + 2k\pi \right )\)
\(f'(x) = \frac{\cos x} {2\sqrt{\sin x}},\ x\in \mathop{\mathop{\bigcup }}\nolimits _{k\in \mathbb{Z}}\left \langle 2k\pi ; \frac{\pi } {2} + 2k\pi \right \rangle \)

9000063305

Část: 
C
Derivace funkce \(f\colon y = \sqrt{\frac{x-1} {x+1}}\) je rovna:
\(f'(x) = \frac{1} {(x+1)^{2}} \sqrt{\frac{x+1} {x-1}},\ x\in (-\infty ;-1)\cup (1;\infty )\)
\(f'(x) = \frac{\sqrt{x-1}} {(x-1)^{2}\sqrt{x+1}},\ x\in (-\infty ;-1)\cup \langle 1;\infty )\)
\(f'(x) = \frac{x-1} {2\sqrt{(x+1)^{3}}} ,\ x\neq - 1\)
\(f'(x) = \frac{x-1} {\sqrt{(x+1)^{3}}} ,\ x\in (-\infty ;-1)\cup \langle 1;\infty )\)

9000063306

Část: 
C
Derivace funkce \(f\colon y =\mathrm{e} ^{\sin 2x}\) je rovna:
\(f'(x) = 2\mathrm{e}^{\sin 2x}\cos 2x,\ x\in \mathbb{R}\)
\(f'(x) = x\mathrm{e}^{\sin 2x}\cos 2x,\ x\in \mathbb{R}\)
\(f'(x) =\mathrm{e} ^{\sin 2x}\sin 2x,\ x\in \mathbb{R}\)
\(f'(x) =\mathrm{e} ^{\cos 2x},\ x\in \mathbb{R}\)