9000063303

Subtema:

Parte:

Project ID:

9000063303

Accepted:

Deriva la siguiente función.

f (x) = \sqrt{\sin x}

f^{'} (x) = \frac{\cos x}{2 \sqrt{\sin x}}, x \in ⋃_{k \in Z} (2 k π; π + 2 k π)

f^{'} (x) = \frac{\sin x}{2 \sqrt{\cos x}}, x \in ⋃_{k \in Z} (2 k π; \frac{π}{2} + 2 k π)

f^{'} (x) = \frac{1}{2 \sqrt{\sin x}}, x \in ⋃_{k \in Z} (2 k π; π + 2 k π)

f^{'} (x) = \frac{\cos x}{2 \sqrt{\sin x}}, x \in ⋃_{k \in Z} [2 k π; \frac{π}{2} + 2 k π]

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