Časť:
Project ID:
9000063305
Accepted:
1
Derivácia funkcie \(f\colon y = \sqrt{\frac{x-1}
{x+1}}\)
je rovná:
\(f'(x) = \frac{1}
{(x+1)^{2}} \sqrt{\frac{x+1}
{x-1}},\ x\in (-\infty ;-1)\cup (1;\infty )\)
\(f'(x) = \frac{\sqrt{x-1}}
{(x-1)^{2}\sqrt{x+1}},\ x\in (-\infty ;-1)\cup \langle 1;\infty )\)
\(f'(x) = \frac{x-1}
{2\sqrt{(x+1)^{3}}} ,\ x\neq - 1\)
\(f'(x) = \frac{x-1}
{\sqrt{(x+1)^{3}}} ,\ x\in (-\infty ;-1)\cup \langle 1;\infty )\)