We are given the equation \(x^2-6x-y=-7\), where \(x\) and \(y\) are real numbers. Choose the picture showing (in red color) the solution set of the equation.
Describe the set of all ordered pairs of real numbers in the form \([x;y]\) that are solutions to the followig equation.
\[
\frac{x-7}{y+1}=5
\]
Which of the descriptions of our solution set is correct?
Describe the set of all ordered pairs of real numbers in the form \(\left[x;y\right] \) that are solutions to the following equation.
\[\frac{y+2}{x-4}=3\]
Which of the descriptions of our solution set is incorrect?
Solve the given system of equations in the set of real numbers.
\[\begin{aligned}
x-y&=2\\
x^2-y^2&=2\\
\end{aligned}\]
In the following list identify a true statement.
Solve the given system of equations in the set of real numbers.
\[\begin{aligned}
x+y&=4+\frac{1}{27}\\
x\cdot y&=\frac{4}{27}\\
\end{aligned}\]
In the following list identify a true statement.
Solve the given system of equations in the set of real numbers.
\[\begin{aligned}
x^2+y&=2\\
2x-y+3&=0\\
\end{aligned}
\]
In the following list identify a true statement.
The numbers \(x\) and \(y\) are opposite of each other.
The sum of the numbers \(x\) and \(y\) is equal to \(-2\).
The arithmetic mean of numbers \(x\) and \(y\) is equal to \(2\).
Solve the given system of equations in the set of real numbers.
\[
\begin{aligned}
x+y&=-5\\
1+\sqrt{2x+4y}&=\sqrt{x+3y}\\
\end{aligned}\]
In the following list identify a true statement.
Assuming \( x \in \mathbb{R}\), find the solution set of the following system of inequalities.
\[\begin{aligned}
2x- [x-(2x+1)]\cdot 3 &> (3+x)-2(1-x)-2x+6 \\
x^2-3\cdot [x-2x(1-x)] &< 5(10-x^2)-2x
\end{aligned}\]
Consider the system
\[\begin{aligned}
y & = \frac{k}
{x}, & &
\\y & = a, & &
\end{aligned}\]
where \(a\),
\(k\) are real
parameters and \(x\),
\(y\) are real
variables. Determine the conditions for \(a\) and \(k\) so that the system has a unique solution in \(\mathbb{R}^{+}\times \mathbb{R}^{-}\).
Determine all the values of the parameter
\(c\in \mathbb{R}\)
so that the following system has two solutions in
\(\mathbb{R}\times \mathbb{R}\).
\[ \begin{alignedat}{80}
&x^{2} & + &2y^{2} & = 6 & & & & & &
\\ &x & + &y & = c & & & & & &
\\\end{alignedat}\]