9000104307 Level: BAssuming a∈(0;2), solve the following inequality. a(a−2)x>1(−∞;1a(a−2))(1a(a−2);∞)∅{1a(a−2)}
9000104310 Level: BAssuming a∈(0;1), solve the following inequality. 2a(1−a)x>3(32a(1−a);∞)(−32a(1−a);∞)(−32a(1−a);32a(1−a))(−∞;32a(1−a))
2000019105 Level: CConsider the following equation with a parameter a. 2x−ax−5=a Choose the table that summarizes solutions of the equation according to the value of a.ParameterSolution seta∈{2;10}∅a∈R∖{2;10}{4aa−2}ParameterSolution seta=5∅a≠5{4aa−2}ParameterSolution seta=2∅a≠5{4aa−2}
2000019106 Level: CConsider the following equation with a parameter a. x−ax−3=2a Choose the table that summarizes solutions of the equation according to the value of a.ParameterSolution seta∈{12;3}∅a∈R∖{12;3}{5a2a−1}ParameterSolution seta=3∅a≠3{5a2a−1}ParameterSolution seta=12∅a≠12{5a2a−1}
2000019109 Level: CDetermine the set of all values of the parameter a∈R∖{0} for which the equation has a unique solution. x−1x=2−a3aR∖{12;0}R∖{0;2;12}R∖{0}R∖{13;0;2;1}
2000019110 Level: CDetermine the set of all values of the real parameter a for which the equation has a unique solution. a(x+2)−3(x−1)x+1=1R∖{−6;4}R∖{−1;−2;1}R∖{0;−1}R∖{4}
9000104503 Level: CSolve the following equation with unknown x and a real parameter a∈R. a2(x−1)ax−2=2ParameterSolution seta=0∅a=2R∖{1}a∉{0;2}{a+2a}ParameterSolution seta∈{0;2}Ra∉{0,2}{a+2a}ParameterSolution seta=0∅a=2Ra∉{0;2}{a+2a}ParameterSolution seta=0R∖{1}a=2∅a∉{0;2}{a+2a}
9000104504 Level: CSolve the following equation with unknown x and a real parameter a∈R∖{0}. 1x−a+1=1aParameterSolution seta=1∅a∉{0,1}{a(a−2)a−1}ParameterSolution seta=1R∖{1}a∉{0;1}{a(a−2)a−1}ParameterSolution seta=1Ra∉{0,1}{a(a−2)a−1}
9000140001 Level: CConsider the equation 4ax−1ax+2a=4 with unknown x and a parameter a∈R∖{0}. Identify a true statement.If a=12, then the solution is x∈R∖{0}.If a=12, then the equation has no solution.If a=12, then the solution is x∈R.
9000140004 Level: CSolve the following equation with unknown x and a real parameter a∈R. a2(x−1)ax−3=3ParameterSolution seta=0∅a=3R∖{1}a∉{0;3}{a+3a}ParameterSolution seta=0∅a=3{1}a∉{0;3}{a+3a}ParameterSolution seta∈{0;3}∅a∉{0;3}{a+3a}ParameterSolution seta=0∅a=3Ra∉{0;3}{a+3a}