9000104504 | math4u.vsb.cz

SubArea:

Equations and inequalities with parameters

Level:

Project ID:

9000104504

Accepted:

1

Clonable:

0

Easy:

0

Solve the following equation with unknown

x

and a real parameter

a \in R ∖ {0}

.

\frac{1}{x - a} + 1 = \frac{1}{a}

\begin{array}{cc} Parameter & Solution set \\ a = 1 & \emptyset \\ a \notin {0, 1} & {\frac{a (a - 2)}{a - 1}} \end{array}

\begin{array}{cc} Parameter & Solution set \\ a = 1 & R ∖ {1} \\ a \notin {0; 1} & {\frac{a (a - 2)}{a - 1}} \end{array}

\begin{array}{cc} Parameter & Solution set \\ a = 1 & R \\ a \notin {0, 1} & {\frac{a (a - 2)}{a - 1}} \end{array}