Consider the following equation.
\[
|2x - 4| = 5x - 7
\]
Solving the equation on the intervals where it is possible to evaluate the absolute
value we get equations on partial subintervals as follows.
\[\begin{aligned}
\text{for }x &\in (-\infty ;2)\colon &\text{for }x &\in [ 2;\infty )\colon & & & &
\\ - 2x + 4 & = 5x - 7 &2x - 4 & = 5x - 7 & & & &
\\ - 7x & = -11 & - 3x & = -3 & & & &
\\x & = \frac{11}
{7} &x & = 1 & & & &
\end{aligned}\]
Find the solution set of the original equation.