C

9000031106

Część: 
C
Rozwiąż następujący układ równań i wybierz poprawną odpowiedź. \[\begin{aligned} \sqrt{x + y} & = \left |x\right | & & \\x + y & = 4 & & \end{aligned}\]
Dwa rozwiązania \(\left [x_{1},y_{1}\right ]\), \(\left [x_{2},y_{2}\right ]\), gdzie \(x_{1} = -x_{2}\).
Nie ma rozwiązania.
Tylko jedno rozwiązanie.
Dwa rozwiązania \(\left [x_{1},y_{1}\right ]\), \(\left [x_{2},y_{2}\right ]\), gdzie \(x_{1} = x_{2}\).

9000028410

Część: 
C
Find the condition which is equivalent to the fact that the equation \(ax^{2} + bx + c = 0\) with \(x\in \mathbb{R}\) and real coefficients \(a\), \(b\), \(c\) has two solutions and one of the solutions is a reciprocal value of the second solution.
\(b^{2} - 4ac > 0\text{ and }\frac{c} {a} = 1\)
\(b^{2} - 4ac > 0\text{ and }a = c\)
\(b^{2} - 4ac > 0\text{ and }\frac{c} {a} = -1\)
\(b^{2} - 4ac > 0\text{ and }a = -c\)

9000028409

Część: 
C
Find the condition which is equivalent to the fact that the equation \(ax^{2} + bx + c = 0\) with \(x\in \mathbb{R}\) and real coefficients \(a\), \(b\), \(c\) does not have a real solution.
\((b^{2} - 4ac < 0\text{ and }a\not = 0)\text{ or }(a = b = 0\text{ and }c\not = 0)\)
\(b^{2} - 4ac < 0\)
\(b^{2} - 4ac < 0\text{ and }a\not = 0\)
\((b^{2} - 4ac < 0\text{ and }a\not = 0)\text{ or }(ab = 0\text{ and }c\not = 0)\)

9000028408

Część: 
C
Find the condition which is equivalent to the fact that the equation \(ax^{2} + bx + c = 0\) with \(x\in \mathbb{R}\) and real coefficients \(a\), \(b\), \(c\) has two real solutions and one of the solutions is bigger than the other one.
\(b^{2} - 4ac > 0\text{ and }a\not = 0\)
\(b^{2} - 4ac\not = 0\text{ and }a\not = 0\)
\(- \frac{b} {2a} > \frac{\sqrt{b^{2 } -4ac}} {2a} \)
\(- \frac{b} {2a} < \frac{\sqrt{b^{2 } -4ac}} {2a} \)

9000028407

Część: 
C
Find the condition which is equivalent to the fact that the equation \(ax^{2} + bx + c = 0\) with \(x\in \mathbb{R}\) and real coefficients \(a\), \(b\), \(c\) has a unique positive and a unique negative real solution.
\(b^{2} - 4ac > 0\text{ and }\frac{c} {a} < 0\)
\(b^{2} - 4ac > 0\text{ and } - \frac{b} {2a} < 0\)
\(\left (\frac{c} {a} < 0\right )\text{ and }\left (\frac{b} {a} > 0\right )\)
\(\left (\frac{c} {a} < 0\right )\text{ and }\left (\frac{b} {a} < 0\right )\)