1003162303 Level: CFind all the values of the real parameter m such that f(x)=3(x+m)2−2 is increasing on (0;∞).m∈[0;∞)m∈(−∞;0)m∈(−∞;0]m∈(−∞;2]
1003162302 Level: CFind all the values of the real parameter m such that f(x)=−2(x−m)2+3 is an even function.m=0m=3m=−3m∈(−∞;∞)
1003162301 Level: CFind all the values of the real parameter a such that f(x)=ax2−2 is decreasing on (0;∞).a∈(−∞;0)a∈(0;∞)a∈[2;+∞)a∈(−∞;2]
1003108312 Level: BThe graph of the function f is a parabola, vertex of which is [6;0] and f(2)=8 is given. Find the function f.f(x)=12(x−6)2f(x)=−12(x−6)2f(x)=12(x+6)2f(x)=12x2+6
1003108311 Level: BThe quadratic function f has the minimum at x=−2 and its graph passes through the points [0;13], [−1;4]. Find the function f.f(x)=3(x+2)2+1f(x)=−59(x−2)2+9f(x)=59(x−2)2+9f(x)=3(x+2)2−1
1003108310 Level: BThe graph of the quadratic function f has the vertex at the point [3;−1] and it passes through the point [−1;3]. Find the function f.f(x)=14x2−32x+54f(x)=14x2+32x+54f(x)=−14x2+32x−134f(x)=x2+6x+8
1003108309 Level: BThe graph of the quadratic function f intersects coordinate axes at the points [−3;0], [1;0], [0;32]. Find the function f.f(x)=−12(x+1)2+2f(x)=−12(x+1)2+12f(x)=−12(x−1)2+2f(x)=12(x−1)2+2
1003108308 Level: BWhich of the following information are insufficient to determine quadratic function uniquely?two intersection points with the x-axis and x-coordinate of the vertextwo intersection points with the x-axis and y-coordinate of the vertextwo intersection points with the x-axis and any other point of the functioncoordinates of the vertex and the intersection with the y-axis
1003108307 Level: CChoose the triple of points, such that the graph of any of the functions f(x)=ax2+c, where a∈R∖0, c∈R, does not pass through all three points.[−2;5], [2;1], [0;3][−2;5], [2;5], [0;3][−2;5], [2;5], [0;7][−2;5], [0;0], [1;1]
1003108306 Level: BThe x-axis is the tangent line of the graph of the quadratic function f. The point of tangency has the coordinates [−2;0]. Given f(−1)=−4, find the function f.f(x)=−4x2−16x−16f(x)=−4x2−16x+16f(x)=−49x2+169x−169f(x)=4x2−16x+16