Find a number which is a sum of one half of the bigger solution of
\[
x^{2} - 10x + 24 = 0
\]
and a double of the smaller solution of
\[
-x^{2} + 10x - 16 = 0.
\]
Identify a true statement referring to the solution of the following equation.
\[
6x - 13\sqrt{x} + 6 = 0
\]
Hint: Use the substitution \(y = \sqrt{x}\).
The solutions \(x_{1}\)
and \(x_{2}\)
satisfy \(x_{1} = \frac{1}
{x_{2}} \).
The equation has a unique solution
\(x_{1}\). This solution
satisfies \(x_{1} < 1\).
The equation has a unique solution
\(x_{1}\). This solution
satisfies \(x_{1} > 1\).
The equation does not have a solution in
\(\mathbb{R}\).