Trigonometric equations and inequalities

1003086103

Level: 
C
The solution set of the equation \( 2\sin x + \mathrm{tg}\,x = 0 \), \( x\in\mathbb{R} \) is:
\( \bigcup\limits_{k\in\mathbb{Z}}\left\{k\pi;\frac{2\pi}3+2k\pi;\frac{4\pi}3+2k\pi\right\} \)
\( \bigcup\limits_{k\in\mathbb{Z}}\left\{2k\pi;\frac{2\pi}3+2k\pi;\frac{4\pi}3+2k\pi\right\} \)
\( \bigcup\limits_{k\in\mathbb{Z}}\left\{k\pi;\frac{5\pi}6+k\pi;\frac{7\pi}6+k\pi\right\} \)
\( \bigcup\limits_{k\in\mathbb{Z}}\left\{k\pi;\frac{5\pi}6+2k\pi;\frac{7\pi}6+2k\pi\right\} \)

1003085807

Level: 
B
For which \( x\in\left(-\frac{\pi}2;\ \frac{\pi}2\right) \) is the inequality \( \mathrm{tg}\,3x < -1 \) true?
\( x\in\left(-\frac{\pi}2;-\frac{5\pi}{12}\right)\cup\left(-\frac{\pi}6;-\frac{\pi}{12}\right)\cup\left(\frac{\pi}6;\frac{\pi}4\right) \)
\( x\in\left(-\frac{\pi}6;-\frac{\pi}{12}\right)\cup\left(\frac{\pi}6;\frac{\pi}4\right) \)
\( x\in\left(-\frac{\pi}2;-\frac{5\pi}{12}\right)\cup\left(-\frac{\pi}6; - \frac{\pi}{12}\right) \)
\( x\in\left(-\frac{\pi}6; -\frac{\pi}{12}\right)\cup\left(\frac{\pi}{12};\frac{\pi}6\right)\cup\left(\frac{\pi}6;\frac{\pi}4\right) \)