Limits and continuity

1003164302

Level: 
C
Which of the following situations could arise for suitable functions \( f \) and \( g \)?
\( \lim\limits_{x\to2}⁡f(x)=\infty\ \wedge\ \lim\limits_{x\to2}g(x)=\infty\ \wedge\ \lim\limits_{x\to2}[f(x)-g(x)]=\infty \)
\( \lim\limits_{x\to2}⁡f(x)=1\ \wedge\ \lim\limits_{x\to2}g(x)=\infty\ \wedge\ \lim\limits_{x\to2}\frac{f(x)}{g(x)}=1 \)
\( \lim\limits_{x\to2}⁡f(x)=-\infty\ \wedge\ \lim\limits_{x\to2}g(x)=1\ \wedge\ \lim\limits_{x\to2}[f(x)+g(x)]=1 \)
\( \lim\limits_{x\to2}⁡f(x)=-\infty\ \wedge\ \lim\limits_{x\to2}g(x)=-\infty\ \wedge\ \lim\limits_{x\to2}[f(x)\cdot g(x)]=-\infty \)

1003164301

Level: 
C
Which of the following situations could arise for suitable functions \( f \) and \( g \)?
\( \lim\limits_{x\to3} f(x)=\infty\ \wedge\ \lim\limits_{x\to3} g(x)=\infty\ \wedge\ \lim\limits_{x\to3}\frac{f(x)}{g(x)}=5 \)
\( \lim\limits_{x\to3} f(x)=1\ \wedge\ \lim\limits_{x\to3} g(x)=\infty\ \wedge\ \lim\limits_{x\to3}\frac{f(x)}{g(x)}=5 \)
\( \lim\limits_{x\to3} f(x)=\infty\ \wedge\ \lim\limits_{x\to3} g(x)=1\ \wedge\ \lim\limits_{x\to3}\frac{f(x)}{g(x)}=5 \)
\( \lim\limits_{x\to3} f(x)=0\ \wedge\ \lim\limits_{x\to3} g(x)=\infty\ \wedge\ \lim\limits_{x\to3}\frac{f(x)}{g(x)}=5 \)

1003109905

Level: 
B
Choose the proper expression to expand \( \sqrt{x-5}-\sqrt x \) when evaluating the limit \( \lim\limits_{x\to\infty}⁡\!\left(\sqrt{x-5}-\sqrt x-1 \right) \).
\( \frac{\sqrt{x-5}+\sqrt x}{\sqrt{x-5}+\sqrt x} \)
\( \frac{\sqrt{x-5}+\sqrt x+1}{\sqrt{x-5}+\sqrt x+1 } \)
\( \frac{\sqrt{x+5}+\sqrt x}{\sqrt{x+5}+\sqrt x} \)
\( \frac{\sqrt{x-5}}{\sqrt{x-5}} \)
\( \frac{\sqrt{x-5}+\sqrt x-1}{\sqrt{x-5}+\sqrt x-1} \)