Kvadratické rovnice v obore komplex. čísel

9000064504

Časť: 
B
Nájdite hodnoty reálnych koeficientov \(a\), \(b\) a \(c\) tak, aby kvadratická rovnica \[ ax^{2} + bx + c = 0 \] mala komplexné korene \(x_{1, 2} = 1\pm \frac{\mathrm{i}} {2}\).
\(a = 4\text{, }b = -8\text{, }c = 5\)
\(a = 1\text{, }b = -4\text{, }c = 5\)
\(a = 4\text{, }b = 8\text{, }c = 5\)
\(a = 1\text{, }b = 4\text{, }c = 5\)

9000069910

Časť: 
B
Určte množinu všetkých hodnôt parametra \(p\in \mathbb{R}\), pre ktoré má rovnica \[ x^{2} + 2px + 16 = 0 \] imaginárne korene, tj. komplexné korene s nenulovou imaginárnou časťou.
\(p\in (-4;4)\)
\(p\in (-\infty ;4)\)
\(p\in (4;\infty )\)
\(p\in \emptyset\)

1003107501

Časť: 
C
Určte komplexné korene kvadratickej rovnice. \[ 2\mathrm{i}\,x^2 - 5\mathrm{i}\,x = 0 \]
\( x_1=0\text{, }\ x_2 = \frac52 \)
\( x_1=0\text{, }\ x_2 = \frac52\mathrm{i} \)
\( x_1=0\text{, }\ x_2 = -\frac52 \)
\( x_1=0\text{, }\ x_2 = -\frac52\mathrm{i} \)

1003107503

Časť: 
C
Určte komplexné korene danej kvadratickej rovnice. \[ (3-\mathrm{i})x^2-(1-2\mathrm{i})x = 0 \]
\( x_1=0\text{, }\ x_2=\frac12-\frac12\mathrm{i} \)
\( x_1=0\text{, }\ x_2=-\frac12+\frac12\mathrm{i} \)
\( x_1=0\text{, }\ x_2=\frac12+\frac12\mathrm{i} \)
\( x_1=0\text{, }\ x_2=-\frac12-\frac12\mathrm{i} \)

1003107504

Časť: 
C
Určte komplexné korene danej kvadratickej rovnice. \[ 16\mathrm{i}x^2 - 9\mathrm{i}^3 = 0 \]
\( x_1=\frac34\mathrm{i}\text{, }\ x_2=-\frac34\mathrm{i} \)
\( x_1=\frac34\text{, }\ x_2=-\frac34\)
\( x_1=\frac43\mathrm{i}\text{, }\ x_2=-\frac43\mathrm{i} \)
\( x_1=\frac43\text{, }\ x_2=-\frac43 \)

1003107505

Časť: 
C
Určte komplexné korene danej kvadratickej rovnice. \[ 4\mathrm{i}x^2 + 1 = 0 \]
\( x_1=\frac{\sqrt2}4+\frac{\sqrt2}4\mathrm{i}\text{, }\ x_2=-\frac{\sqrt2}4-\frac{\sqrt2}4\mathrm{i} \)
\( x_1=-\frac{\sqrt2}4+\frac{\sqrt2}4\mathrm{i}\text{, }\ x_2=\frac{\sqrt2}4-\frac{\sqrt2}4\mathrm{i} \)
\( x_1=\frac12+\frac12\mathrm{i}\text{, }\ x_2=-\frac12-\frac12\mathrm{i} \)
\( x_1=-\frac12+\frac12\mathrm{i}\text{, }\ x_2=\frac12-\frac12\mathrm{i} \)