2010013201
Časť:
A
Určte komplexné korene danej kvadratickej rovnice.
\[ 3x^2 + 8 = 0 \]
\( x_1=-\frac{2\sqrt{6}}3\mathrm{i},\ x_2=\frac{2\sqrt{6}}3\mathrm{i} \)
\( x_1=-\frac{\sqrt{6}}3\mathrm{i},\ x_2=\frac{\sqrt{6}}3\mathrm{i} \)
\( x_1=-\frac{\sqrt{12}}3\mathrm{i},\ x_2=\frac{\sqrt{12}}3\mathrm{i} \)
\( x_1=-\frac{\sqrt{6}}6\mathrm{i},\ x_2=\frac{\sqrt{6}}6\mathrm{i} \)