Level:
Project ID:
1103189001
Accepted:
1
Clonable:
0
Easy:
0
Find the general form of the equation of the plane \( \alpha \) that is perpendicular to the straight line \( p \) given by:
\begin{align*}
x&=7+t, \\
y&=2t, \\
z&=4-t;\ t\in\mathbb{R},
\end{align*}
and passes through the point \( A=[1;0;4] \). Consequently, find the coordinates of the point \( B \) which is the point of intersection of \( p \) and \( \alpha \) (see the picture).
\( \alpha\colon x+2y-z+3=0;\ B=[6;-2;5] \)
\( \alpha\colon x+2y-z-3;\ B=[6;-2;5] \)
\( \alpha\colon x+2y-z-3=0;\ B=[8;2;3] \)
\( \alpha\colon x+2y-z+3=0;\ B=[8;2;3] \)