1103189001

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1103189001
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Find the general form of the equation of the plane \( \alpha \) that is perpendicular to the straight line \( p \) given by: \begin{align*} x&=7+t, \\ y&=2t, \\ z&=4-t;\ t\in\mathbb{R}, \end{align*} and passes through the point \( A=[1;0;4] \). Consequently, find the coordinates of the point \( B \) which is the point of intersection of \( p \) and \( \alpha \) (see the picture).
\( \alpha\colon x+2y-z+3=0;\ B=[6;-2;5] \)
\( \alpha\colon x+2y-z-3;\ B=[6;-2;5] \)
\( \alpha\colon x+2y-z-3=0;\ B=[8;2;3] \)
\( \alpha\colon x+2y-z+3=0;\ B=[8;2;3] \)