1003158804 Level: BWhich of the following statements is not true about the equation? \[ \log_x16+\log_{\frac1x}4=2 \]The solution is an odd number.The solution is \( x=2 \).The solution is an even number.The solution is a prime number.
1003158803 Level: BSolve \[ \log_{\frac12}(x)+2=3\log_2(x) \text{ .} \]\( x=\sqrt2 \)\( x=2 \)\( x=-1 \)Equation has no solution.
1003158802 Level: BFind the solution set of the following equation. \[ \log_{0.2}(x)-4\log_{0.04}(x)=\log_5(x) \]\( (0;\infty) \)\( \mathbb{R} \)\( \emptyset \)\( [ 0;\infty) \)
1003158801 Level: BSolve \[ \log_2(x)-\log_4(x)=1\text{ .} \]\( x=4 \)\( x=2 \)\( x_1=\frac12\text{, }x_2=4 \)\( x_1=-1\text{, }x_2=2 \)
9000004901 Level: CSolve the following inequality. \[ \log _{0.3}x\geq \log _{0.3}5 \]\(x\in (0;5] \)\(x\in (0;\infty )\)\(x\in (-\infty ;5] \)\(x\in [ 5;\infty )\)
9000003806 Level: BIn the following list identify an equation such that neither \(x = 5\) nor \(x = 3\) is the solution of this equation.\(\log _{3}(1 - x) =\log _{3}(x + 16 - x^{2})\)\(\log (54 - x^{3}) = 3\cdot \log x\)\(\log _{5}(x^{2} - 17) =\log _{5}(x + 3)\)\(\log (x - 2) -\log (4 - x) = 1 -\log (13 - x)\)
9000003808 Level: BIdentify one statement which is true for the following equation. \[ \log (x - 13) -\log (x - 3) = 1 -\log 2 \]The equation does not have a solution.The equation has two solutions.The equation has a unique solution. This solution is a noninteger rational number.The solution is \(x = 0\).The equation has a unique solution. This solution is a positive integer.The equation has a unique solution. This solution is a negative integer.
9000003805 Level: BSolve the following equation. \[ \log x^{2}\cdot \log \sqrt{x} -\log \frac{1} {x} = 2 \]\(x_{1} = \frac{1} {100}\), \(x_{2} = 10\)\(x_{1} = -2\), \(x_{2} = 1\)\(x_{1} = - \frac{1} {100}\), \(x_{2} = 10\)\(x_{1} = -1\), \(x_{2} = 2\)
9000003809 Level: CFind the solution set of the following inequality. \[ \log _{0.5}(x^{2} - 2x) >\log _{ 0.5}3 \]\((-1;0)\cup (2;3)\)\((-\infty ;0)\cup (2;\infty )\)\((0;2)\)\((-\infty ;-1)\cup (0;2)\cup (3;\infty )\)\((-\infty ;-1)\cup (3;\infty )\)\((-1;3)\)