Level:
Project ID:
2000019201
Accepted:
0
Clonable:
0
Easy:
0
People in Kocourkov pay by coins named groschen. Their coins are worth \(1\), \(5\) or \(7\) groschen. Martin and Petr, who live in Kocourkov, emptied their saving boxes and started counting their saved coins. They found out that Petr had \(6\) pieces of each type of a coin more than Martin, who had \(40\) coins in total. They were surprised to find out that Martin has the same number of \(1\)-groschen and \(7\)-groschen coins in total as Petr has of \(5\)-groschen ones. Petr was proud to have \(78\) groschen more than Martin, who was only \(2\) short of having \(200\) groschen. Which of the following systems can be used to find out how many coins of each type both boys have?
\[\begin{aligned}
x +5y + 7z & = 198 & &
\\ x - y+z & = 6 & &
\\ x +y+z & = 40 & &
\end{aligned}\]
\[\begin{aligned}
x +5y+7z & = 198 & &
\\x - y+z & = 6 & &
\\(x+6) +5(y+6)+7(z+6) & = 276 & &
\end{aligned}\]
\[\begin{aligned}
x +5y+7z & = 198 & &
\\x + y-z & = 6 & &
\\(x+6) +5(y+6)+7(z+6) & = 276 & &
\end{aligned}\]
\[\begin{aligned}
x +5y+7z & = 202 & &
\\x - y+z & = 6 & &
\\(x+6) +(y+6)+(z+6) & = 58 & &
\end{aligned}\]
\[\begin{aligned}
x +5y+7z & = 198 & &
\\x - y+z & = 6 & &
\\x +5y+7z & = 40 & &
\end{aligned}\]
\[\begin{aligned}
x +5y+7z & = 198 & &
\\x - y+z & = 6 & &
\\(x-6) +5(y-6)+7(z-6) & = 276 & &
\end{aligned}\]