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Consider an object thrown at an angle of ${30}^{\circ }$ above the horizontal with the initial velocity of $40\frac{\mathrm{m}}{\mathrm{s}}$. How long does it take for the object to reach its maximum height? $$$$ Note: The height $y$ of an object thrown is described by the formula $y=v_{0}t\sin \alpha -\frac{1}{2}g{t}^2$, where $v_0$ is the initial velocity, $g$ is gravitational acceleration (count with the rounded value $10\frac{\mathrm{m}}{{\mathrm{s}}^2}$), $t$ is the time period of the object motion in seconds, and $\alpha$ is the angle to the horizontal at which the object is thrown.