1003047301 Level: AWhich of the following expressions describes the correct calculation of the limit? L=limn→∞n3+2n−32n3+5L=limn→∞1+2n2−3n32+5n3=12L=∞3+2⋅∞−32⋅∞3+5=∞L=∞3+2⋅∞−32⋅∞3+5=0L=limn→∞n(n2+2)−32n3+5=−35L=limn→∞(n2+3)(n−1)2(n3+52)=0
1003047302 Level: AChoose the best first step to take in order to evaluate the limit of the following sequence. (4n5+n4−n3+27n4−2n2+7n)n=1∞We factor out n4 in the numerator and in the denominator separately.We factor out n5 in the numerator and in the denominator separately.We factorize a polynomial in the denominator.We divide the denominator by n4.We divide the numerator by n5.
1003047305 Level: AThe sequence (12n3+5n+12n3−6)n=1∞is convergent and limn→∞12n3+5n+12n3−6=6.is convergent and limn→∞12n3+5n+12n3−6=0.is convergent and limn→∞12n3+5n+12n3−6=12.is divergent and limn→∞12n3+5n+12n3−6=∞.has no limit.