9000005803
Level:
A
Identify an analytic expression of a linear function
\(f\) which
satisfies \(f(-2) = 5\)
and \(f(4) = 2\).
\(f\colon y = -\frac{1}
{2}x + 4\)
\(f\colon y = x - 2\)
\(f\colon y = -x + 6\)
\(f\colon y = -2x + 1\)
A
9000004209
Level:
A
The linear function \(g\)
is graphed in the picture. Find the analytic expression for the function
\(g\).
\(y = -\frac{3}
{2}x\)
\(y = \frac{3}
{2}x\)
\(y = \frac{2}
{3}x\)
\(y = -\frac{2}
{3}x\)
9000005702
Level:
A
Given the linear function \(f(x) = -2x + 3\),
evaluate \(f(2) + f(-2)\).
\(6\)
\(0\)
\(3\)
\(- 8\)
9000004903
Level:
A
Find the domain of the function \(f\colon y = \frac{3}
{\log _{5}(x-4)}\).
\(\mathrm{Dom}(f) = (4;5)\cup (5;\infty )\)
\(\mathrm{Dom}(f) = (0;\infty )\setminus \{4\}\)
\(\mathrm{Dom}(f) = (-4;\infty )\setminus \{5\}\)
\(\mathrm{Dom}(f) = (4;\infty )\)
9000005706
Level:
A
Let the function \(f\)
be defined as a linear function with graph passing through the points
\(A = [2;3]\) and
\(B = [-1;6]\). Find an analytic
expression for the function \(f\).
\(f(x)= -x + 5\)
\(f(x) = x + 1\)
\(f(x)= 2x - 1\)
\(f(x) = -5x + 1\)
9000004904
Level:
A
In the following list identify a function with a domain
\(\left (-\infty ; \frac{2}
{3}\right ).\)
\(y =\log (2 - 3x)\)
\(y =\log (3x - 2)\)
\(y = -\log (3x - 2)\)
\(y =\log (2x - 3)\)
\(y =\log (3 - 2x)\)
none of the above
9000005709
Level:
A
Consider the linear function \(f(x)= -\frac{4}
{3}x + 4\).
Find the intersection point of the graph of
\(f\) with
\(x\)-axis.
\([3;0]\)
\([0;-6]\)
\([0;-4]\)
\([6;0]\)
9000004906
Level:
A
Identify a possible analytic expression for the function
\(f\)
graphed in the picture.
\(y =\log _{2}x\)
\(y =\log _{0.2}x\)
\(y =\log _{0.5}x\)
\(y =\log _{5}x\)
9000005710
Level:
A
Consider the linear function \(f(x) = 4x + 4\).
Find the intersection point of the graph of
\(f\) with
\(y\)-axis.
\([0;4]\)
\([-1;0]\)
\([-4;0]\)
\([0;0]\)
9000004909
Level:
A
Identify a possible analytic expression for the function
\(g\)
graphed in the picture.
\(y =\log _{3}(x + 2) - 1\)
\(y =\log _{\frac{1}
{3} }(x + 2) - 1\)
\(y =\log _{3}(x - 2) + 1\)
\(y =\log _{\frac{1}
{3} }(x - 2) + 1\)