Find a set of the values of the real parameter
\(a\) which
ensure that the following equation has infinitely many solutions.
\[
3a^{2}x - 2ax + 4 = 6a
\]
Find a set of the values of the real parameter
\(a\) which
ensure that the following equation has infinitely many solutions.
\[
a^{2}x + 1 = a^{2} + ax
\]
Consider equation
\[
\frac{x - 3}
{a} = \frac{a - x}
{3} + 2
\]
with an unknown \(x\in \mathbb{R}\)
and a real parameter \(a\in \mathbb{R}\setminus \{0\}\).
Identify a statement which is not true.
For \(a\mathrel{\in }\{ - 3;0\}\) we
have \(x = \frac{1}
{a+3}\).
For \(a\mathrel{\notin }\{ - 3;0\}\) we
have \(x = a + 3\).
If \(a = -3\),
then the equation has infinitely many solutions.