9000104505 | math4u.vsb.cz

SubArea:

Equations and inequalities with parameters

Level:

Project ID:

9000104505

Accepted:

1

Clonable:

0

Easy:

0

Solve the following equation with unknown

x

and a real parameter

a \in R ∖ {- 3; 3}

.

\frac{a - x}{a - 3} - \frac{6 a}{a^{2} - 9} = \frac{x - 3}{a + 3}

\begin{array}{cc} Parameter & Solution set \\ a = 0 & \emptyset \\ a \notin {- 3; 0; 3} & {\frac{a^{2} - 9}{2 a}} \end{array}

\begin{array}{cc} Parameter & Solution set \\ a = 0 & R \\ a \notin {- 3; 0; 3} & {\frac{a^{2} - 9}{2 a}} \end{array}

\begin{array}{cc} Parameter & Solution set \\ a = 0 & R ∖ {0} \\ a \notin {- 3; 0; 3} & {\frac{a^{2} - 9}{2 a}} \end{array}