Find the area of the yellow region that is bounded by the parabola and the line as is indicated in the picture. Read all the needed values from the picture.
Four children evaluated the following integral \( I \) on \( (0;\infty) \). Who made a mistake?
\[ I =\int\left(\frac18\sqrt[8]{x^3}+\frac12\sqrt{x^9}-\frac15\sqrt[5]{x^6} \right)\mathrm{d}x \]
Paul: \( I =\frac1{11}\left(x^3\sqrt[8]x+x\sqrt{x^5}-x\sqrt[5]{x^2}\right)+c\text{, }c\in\mathbb{R} \)
Jane: \( I =\frac1{11}\left(x\sqrt[8]{x^3}+x^5\sqrt x-x^2\sqrt[5] x+c\right)\text{, }c\in\mathbb{R} \)
Ann: \( I =\frac1{11}\left(x\sqrt[8]{x^3}+x^5\sqrt x-x^2\sqrt[5]x\right)+c\text{, }c\in\mathbb{R} \)
Miky: \( I =\frac x{11}\sqrt[8]{x^3}+\frac{x^5}{11}\sqrt x-\frac{x^2}{11}\sqrt[5]x+c\text{, }c\in\mathbb{R} \)
Given the function \( F(x)=\frac23\cos x-\frac{x^2}2\cdot\ln4 \), find the function \( f \) such that \( F \) is primitive to \( f \) on \(\mathbb{R} \).