Plane geometry | math4u.vsb.cz

9000090907

Level:

C

Given points

A = [2; m]

and

B = [- 1; 0]

, find

m \in R

such that the line

p

is parallel to the line passes through the points

A

,

B

.

\begin{aligned} p : x & = 3 + 2 t, \\ y & = 5 - t; t \in R \end{aligned}

m = - \frac{3}{2}

m = \frac{3}{2}

m = - \frac{2}{3}

m = 2

does not exist

9000090908

Level:

C

Given points

A = [2; 1]

and

B = [m; 0]

, find

m \in R

such that the line

p

is parallel to the line passes through the points

A

,

B

.

p : 3 x - y + 17 = 0

m = \frac{5}{3}

m = 4

m = \frac{5}{2}

m = - 1

another solution

9000090909

Level:

C

Given lines

p

and

q

, find

m \in R

such that the lines

p

and

q

are parallel.

p : 2 x + m y - 3 = 0, \begin{aligned} q : x & = 1 + t, \\ y & = 2 - t; t \in R \end{aligned}

m = 2

m = - 2

m = 11

m = - \frac{1}{11}

does not exist

9000090910

Level:

C

Given lines

p

and

q

, find

m \in R

such that the line

p

is parallel to

q

.

p : x + 4 y - 3 = 0, \begin{aligned} q : x & = 1 + m t, \\ y & = 2 - 3 t; t \in R \end{aligned}

m = 12

m = - \frac{1}{12}

m = 4

m = \frac{5}{2}

m = - 1

9000090903

Level:

C

Given the line

p : 3 x - 2 y + 11 = 0,

find

m \in R

such that the point

C = [m; 0]

is on the line

p

.

m = - \frac{11}{3}

m = - 1

m = 11

m = - \frac{1}{11}

m = 2

9000090902

Level:

C

Given the parametric line

p

, find

m \in R

such that the point

C = [m; 3]

is on the line

p

.

\begin{aligned} p : x & = 1 - t, \\ y & = - 3 + 2 t; t \in R \end{aligned}

m = - 2

m = 4

m = 11

m = - \frac{11}{3}

m = \frac{3}{2}

9000090901

Level:

C

Given two points

A = [2; 5]

and

B = [- 3; 2]

, identify a number

m \in R

such that the point

C = [1; m]

is on the line

A B

.

m = \frac{22}{5}

m = 20

m = - 3

m = \frac{2}{3}

m = - \frac{5}{2}

9000090904

Level:

C

Given lines

p

and

q

, find

m \in R

such that the lines

p

and

q

are parallel.

p : x - 2 y + 7 = 0, q : m x + 3 y - 11 = 0

m = - \frac{3}{2}

m = \frac{2}{3}

m = \frac{3}{2}

m = - \frac{2}{3}

another solution

9000090905

Level:

C

Given lines

p

and

q

, find

m \in R

such that the lines

p

and

q

are parallel.

p : x - 2 y + 7 = 0, q : x + 3 y + m = 0

does not exist

m = - 7

m = - \frac{2}{7}

m = 2

m = 7

9000090906

Level:

C

Given lines

p

and

q

, find

m \in R

such that the lines

p

and

q

are parallel.

\begin{aligned} p : x & = 1 + t, \\ y & = - 3 t; t \in R, \end{aligned} \begin{aligned} q : x & = 3 - 2 u, \\ y & = 1 + m u; u \in R \end{aligned}

m = 6

m = \frac{3}{2}

m = - \frac{2}{3}

does not exist

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