Geometric sequences

1003109202

Level: 
C
A blouse is on sale and its price was reduced twice, each time by ten percent. The difference between its original and its final price is \( 133\,\mathrm{CZK} \). What was the blouse original price before the discounts?
\( 700\,\mathrm{CZK} \)
\( 665\,\mathrm{CZK} \)
\( 1\,330\,\mathrm{CZK} \)
\( 1\,400\,\mathrm{CZK} \)
\( 750\,\mathrm{CZK} \)

1003124706

Level: 
A
The first term of a geometric sequence is \( 5 \) and the fourth term is \( 40 \). Find the \( n \)th term.
\( a_n=5\cdot2^{n-1} \), \( n\in\mathbb{N} \)
\( a_n=\frac{5n}2 \), \( n\in\mathbb{N} \)
\( a_n=5\cdot2^n \), \( n\in\mathbb{N} \)
\( a_n=5n \), \( n\in\mathbb{N} \)
\( a_n=5\cdot\left(2^{n}-1\right) \), \( n\in\mathbb{N} \)

1003124705

Level: 
A
The third term of a geometric sequence is \( 3 \) and the common ratio is \( 3 \). Find the \( n \)th term.
\( a_n=3^{n-2} \), \( n\in\mathbb{N} \)
\( a_n=3^{n-1} \), \( n\in\mathbb{N} \)
\( a_n=3^{n} \), \( n\in\mathbb{N} \)
\( a_n=\frac3n \), \( n\in\mathbb{N} \)
\( a_n=3n \), \( n\in\mathbb{N} \)

1003124704

Level: 
A
The \( 10 \)th term of a geometric sequence is \( 1 \) and the \( 15 \)th term is \( -1 \). Find the recursive formula of the sequence.
\( a_1=-1 \), \( a_{n+1}=-a_n \)
\( a_1=1 \), \( a_{n+1}=-a_n \)
\( a_1=-1 \), \( a_{n+1}=a_n \)
\( a_1=1 \), \( a_{n+1}=a_n \)
\( a_1=-1 \), \( a_{n+1}=a_n-1 \)

1003124703

Level: 
A
The second term of a geometric sequence is \( 15 \) and the third term is \( 3 \). Find the recursive formula of the sequence.
\( a_1=75 \), \( a_{n+1} = \frac15a_n \)
\( a_1=3 \), \( a_{n+1} = 5a_n \)
\( a_1=\frac35 \), \( a_{n+1} = \frac15a_n \)
\( a_1=\frac35 \), \( a_{n+1} = 5a_n \)
\( a_1=27 \), \( a_{n+1} = a_n-12 \)

1003124702

Level: 
A
Find the recursive formula of the geometric sequence \( a_n=2\cdot 3^n \), \( n\in\mathbb{N} \).
\( a_1=6 \), \( a_{n+1} = 3a_n \)
\( a_1=2 \), \( a_{n+1} = 3a_n \)
\( a_1=3 \), \( a_{n+1} = 6a_n \)
\( a_1=6 \), \( a_{n+1} = \frac13a_n \)
\( a_1=2 \), \( a_{n+1} = a_n+3 \)

1003124701

Level: 
A
The third term of a geometric sequence is \( 9 \) and the common ratio is \( 3 \). Find the recursive formula of the sequence.
\( a_1=1 \), \( a_{n+1}=3a_n \)
\( a_1=3 \), \( a_{n+1}=a_n+3 \)
\( a_1=9 \), \( a_{n+1}=3a_n \)
\( a_1=3 \), \( a_{n+1}=a_n^2 \)
\( a_1=1\), \(a_{n+1}=\frac13a_n \)