Level:
Project ID:
9000038705
Accepted:
1
Clonable:
0
Easy:
0
The box is on the slope as in the picture. The angle of the slope is
\(\alpha = 45^{\circ }\).
The forces acting on the box are the force of gravity
\(\vec{F_{G}}\) and the
friction \(\vec{F_{t}}\).
The force of gravity can be replaced by two components
\(\vec{F_{1}}\) and
\(\vec{F_{n}}\). (The force
\(\vec{F_{1}}\) is parallel to the slope
and \(\vec{F_{n}}\) is perpendicular to
the slope.) The friction \(F_{t}\) is
given by the formula \(F_{t} = fF_{n}\). The
coefficient of the friction \(f = 0.5\).
Consider the standard acceleration of gravity
\(g = 10\, \mathrm{m\, s^{-2}}\). Find the acceleration of the box.
\(a = \frac{5\sqrt{2}}
{2} \, \mathrm{m\, s^{-2}}\)
\(a = 5\sqrt{2}\, \mathrm{m\, s^{-2}}\)
\(a = 5\sqrt{3}\, \mathrm{m\, s^{-2}}\)
\(a = 0\, \mathrm{m\, s^{-2}}\)
\(a = 5\, \mathrm{m\, s^{-2}}\)
\(a = \frac{5\sqrt{3}}
{2} \, \mathrm{m\, s^{-2}}\)