2010016905

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2010016905
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There are sixty apples left on a tree and twelve of them have worms. We pick six apples at random. What is the probability that at least one of them is without a worm?
\( 1-\frac{\binom{12}{6}}{\binom{60}{6}}\doteq 0.999982 \)
\( 1-\frac{\binom{12}{1}}{\binom{48}{6}}\doteq 0.999999 \)
\( 1-\frac{\binom{12}{1} \cdot \binom{48}{5} }{\binom{60}{6}}\doteq 0.589571 \)
\( \frac{\binom{12}{1}+\binom{12}{2} +\binom{12}{3}+\binom{12}{4}+\binom{12}{5} }{\binom{60}{6}}\doteq 0.000032 \)