Level:
Project ID:
2010013702
Source Problem:
Accepted:
0
Clonable:
1
Easy:
0
The motion of two bodies is given by equations
\[s_1=\frac32t^2+3t+2\mbox{,}\quad s_2=\frac13t^3+\frac{t^2}{2}+1,\]
where the positions \(s_1\) and \(s_2\) are given in meters and the time \(t\) in seconds. Determine at what time both bodies will move at the same speed.
\[\]
Hint: Instantaneous velocity can be expressed as the derivative of a position function \(s(t)\) with respect to time: \(v(t)=\frac{\mathrm{d} s}{\mathrm{d} t}\).
\(t=3\,\mathrm{s}\)
\(t=1\,\mathrm{s}\)
\(t=\sqrt7\,\mathrm{s}\)
The speeds of these bodies will always be different.