Część:
Project ID:
2010013407
Source Problem:
Accepted:
0
Clonable:
1
Easy:
0
Dwa rozwiązania równania
\[
x^{3} + 1 - \mathrm{i} = 0
\]
są równe:
\[
\begin{aligned}x_{1}& = \root{6}\of{2}\left (\cos \frac{\pi}
{4} + \mathrm{i}\sin \frac{\pi}
{4} \right ),&
\\x_{2}& = \root{6}\of{2}\left (\cos \frac{11}
{12}\pi + \mathrm{i}\sin \frac{11}
{12}\pi \right ).
\\ \end{aligned}
\]
Znajdź trzecie rozwiązanie.
\(x_{3} = \root{6}\of{2}\left (\cos \frac{19}
{12}\pi + \mathrm{i}\sin \frac{19}
{12}\pi \right )\)
\(x_{3} = \root{6}\of{2}\left (\cos \frac{7}
{12}\pi + \mathrm{i}\sin \frac{7}
{12}\pi \right )\)
\(x_{3} = \root{6}\of{2}\left (\cos \frac{5}
{12}\pi + \mathrm{i}\sin \frac{5}
{12}\pi \right )\)
\(x_{3} = \root{6}\of{2}\left (\cos \frac{13}
{12}\pi + \mathrm{i}\sin \frac{13}
{12}\pi \right )\)