Trigonometric equations and inequalities

1003086104

Level:

Which of the following equations has exactly two solutions in the interval

[0; π]

3 \sin x - 2 = 0

2 \sin x - 3 = 0

3 \cos x + 2 = 0

3 \sin x + 2 = 0

Level:

The picture shows the graphical solution of an equation. Which equation is it?

\cos x = - \frac{1}{2}

x \in [0; 2 π]

\sin x = - \frac{1}{2}

x \in [0; 2 π]

\cos x = - \frac{\sqrt{3}}{2}

x \in [0; 2 π]

\sin x = - \frac{\sqrt{3}}{2}

x \in [0; 2 π]

Level:

The picture shows the graphical solution of an equation. Which equation is it?

\cos x = - \frac{\sqrt{3}}{2}

x \in [0; 2 π]

\sin x = - \frac{\sqrt{3}}{2}

x \in [0; 2 π]

\sin x = - \frac{1}{2}

x \in [0; 2 π]

\cos x = - \frac{1}{2}

x \in [0; 2 π]

Level:

The picture shows the graphical solution of an equation. Which equation is it?

\sin x = - \frac{\sqrt{3}}{2}

x \in [0; 2 π]

\sin x = - \frac{1}{2}

x \in [0; 2 π]

\cos x = - \frac{\sqrt{3}}{2}

x \in [0; 2 π]

\cos x = - \frac{1}{2}

x \in [0; 2 π]

Level:

The picture shows the graphical solution of an equation. Which equation is it?

\sin x = - \frac{1}{2}

x \in [0; 2 π]

\sin x = - \frac{\sqrt{3}}{2}

x \in [0; 2 π]

\cos x = - \frac{1}{2}

x \in [0; 2 π]

\cos x = - \frac{\sqrt{3}}{2}

x \in [0; 2 π]

Level:

An equation is solved graphically as shown in the picture. The solution is marked in red. Choose the corresponding equation.

\sin x = \frac{\sqrt{3}}{2}

x \in [0; 2 π]

\sin x = \frac{1}{2}

x \in [0; 2 π]

\cos x = \frac{\sqrt{3}}{2}

x \in [0; 2 π]

\cos x = \frac{1}{2}

x \in [0; 2 π]

Level:

An equation is solved graphically as shown in the picture. The solution is marked in red. Choose the corresponding equation.

\sin x = \frac{1}{2}

x \in [0; 2 π]

\sin x = \frac{\sqrt{3}}{2}

x \in [0; 2 π]

\cos x = \frac{\sqrt{3}}{2}

x \in [0; 2 π]

\cos x = \frac{1}{2}

x \in [0; 2 π]

Level:

An equation is solved graphically as shown in the picture. The solution is marked in red. Choose the corresponding equation.

\cos x = \frac{1}{2}

x \in [0; 2 π]

\sin x = \frac{\sqrt{3}}{2}

x \in [0; 2 π]

\cos x = \frac{\sqrt{3}}{2}

x \in [0; 2 π]

\sin x = \frac{1}{2}

x \in [0; 2 π]

Level:

An equation is solved graphically as shown in the picture. The solution is marked in red. Choose the corresponding equation.

\cos x = \frac{\sqrt{3}}{2}

x \in [0; 2 π]

\sin x = \frac{\sqrt{3}}{2}

x \in [0; 2 π]

\cos x = \frac{1}{2}

x \in [0; 2 π]

\sin x = \frac{1}{2}

x \in [0; 2 π]

Level:

An equation is solved graphically as shown in the picture. The solution is marked in red. Choose the corresponding equation.

tg x = \frac{\sqrt{3}}{3}

x \in (- π; π)

tg x = \frac{\sqrt{3}}{2}

x \in (- π; π)

cotg x = \frac{\sqrt{3}}{2}

x \in (- π; π)

cotg x = \frac{\sqrt{3}}{3}

x \in (- π; π)