9000003107
Level:
B
Identify a possible analytic expression for the function graphed in the picture.
\(y = -2 + \frac{1}
{x+1}\)
\(y = 2 + \frac{1}
{x+1}\)
\(y = 2 + \frac{1}
{x-1}\)
\(y = -2 + \frac{1}
{x-1}\)
Rational functions
9000003108
Level:
B
Identify a possible analytic expression for the function graphed in the picture.
\(y = -2 - \frac{1}
{x-1}\)
\(y = -1 - \frac{1}
{x-2}\)
\(y = -2 + \frac{1}
{x-1}\)
\(y = 1 - \frac{1}
{x-2}\)
9000002901
Level:
B
Find the domain of the function \(f\colon y = \frac{1}
{x-2} + 1\).
\(\mathbb{R}\setminus \{2\}\)
\(\mathbb{R}\setminus \{ - 1\}\)
\(\mathbb{R}\setminus \{0\}\)
\(\mathbb{R}\)
9000002903
Level:
B
In the following list identify a point which is on the graph of the function
\(f(x) = \frac{3}
{x} - 5\).
\(A = \left [-6;-\frac{11}
{2} \right ]\)
\(A = \left [-1;-2\right ]\)
\(A = \left [-3;-\frac{5}
{2}\right ]\)
\(A = \left [\frac{1}
{2};-1\right ]\)
9000002906
Level:
B
Find the domain of the function
\(f(x) = - \frac{3}
{x-1} - 2\) if we have to ensure
that the range of \(f\)
is \((-1;1] \).
\((-2;0] \)
\([ - 2;0)\)
\((0;2] \)
\((0;4)\)
9000003101
Level:
A
Identify a possible analytic expression for the function graphed in the picture.
\(y = \frac{1}
{2x}\)
\(y = \frac{2}
{x}\)
\(y = -\frac{2}
{x}\)
\(y = -\frac{1}
{2x}\)
9000003102
Level:
A
Identify a possible analytic expression for the function graphed in the picture.
\(y = -\frac{2}
{x}\)
\(y = \frac{2}
{x}\)
\(y = \frac{1}
{2x}\)
\(y = -\frac{1}
{2x}\)
9000003103
Level:
B
Identify a possible analytic expression for the function graphed in the picture.
\(y = 1 -\frac{2}
{x}\)
\(y = -1 + \frac{2}
{x}\)
\(y = 1 + \frac{2}
{x}\)
\(y = -1 -\frac{2}
{x}\)
9000003104
Level:
B
Identify a possible analytic expression for the function graphed in the picture.
\(y = -2 -\frac{1}
{x}\)
\(y = 2 + \frac{1}
{x}\)
\(y = -2 + \frac{1}
{x}\)
\(y = 2 -\frac{1}
{x}\)
9000003105
Level:
B
Identify a possible analytic expression for the function graphed in the picture.
\(y = \frac{1}
{x-2}\)
\(y = - \frac{1}
{x-2}\)
\(y = - \frac{1}
{x+2}\)
\(y = \frac{1}
{x+2}\)