9000003106 Level: BIdentify a possible analytic expression for the function graphed in the picture.\(y = \frac{2} {x+1}\)\(y = \frac{1} {x+2}\)\(y = - \frac{1} {x+2}\)\(y = \frac{1} {x-1}\)
9000002910 Level: AConsider a rectangle with area of \(5\, \mathrm{cm}^{2}\). Find the formula which relates side \(a\) to the side \(b\) of this rectangle.\(b = \frac{5} {a}\), \(a\in (0,\infty )\)\(b = 5a\), \(a\in (0,\infty )\)\(b = \frac{10} {a} \), \(a\in (0,\infty )\)\(b = \frac{25} {a} \), \(a\in (0,\infty )\)
9000003107 Level: BIdentify a possible analytic expression for the function graphed in the picture.\(y = -2 + \frac{1} {x+1}\)\(y = 2 + \frac{1} {x+1}\)\(y = 2 + \frac{1} {x-1}\)\(y = -2 + \frac{1} {x-1}\)
9000003108 Level: BIdentify a possible analytic expression for the function graphed in the picture.\(y = -2 - \frac{1} {x-1}\)\(y = -1 - \frac{1} {x-2}\)\(y = -2 + \frac{1} {x-1}\)\(y = 1 - \frac{1} {x-2}\)
9000002901 Level: BFind the domain of the function \(f\colon y = \frac{1} {x-2} + 1\).\(\mathbb{R}\setminus \{2\}\)\(\mathbb{R}\setminus \{ - 1\}\)\(\mathbb{R}\setminus \{0\}\)\(\mathbb{R}\)
9000003101 Level: AIdentify a possible analytic expression for the function graphed in the picture.\(y = \frac{1} {2x}\)\(y = \frac{2} {x}\)\(y = -\frac{2} {x}\)\(y = -\frac{1} {2x}\)
9000003102 Level: AIdentify a possible analytic expression for the function graphed in the picture.\(y = -\frac{2} {x}\)\(y = \frac{2} {x}\)\(y = \frac{1} {2x}\)\(y = -\frac{1} {2x}\)
9000003103 Level: BIdentify a possible analytic expression for the function graphed in the picture.\(y = 1 -\frac{2} {x}\)\(y = -1 + \frac{2} {x}\)\(y = 1 + \frac{2} {x}\)\(y = -1 -\frac{2} {x}\)
9000003104 Level: BIdentify a possible analytic expression for the function graphed in the picture.\(y = -2 -\frac{1} {x}\)\(y = 2 + \frac{1} {x}\)\(y = -2 + \frac{1} {x}\)\(y = 2 -\frac{1} {x}\)
9000003105 Level: BIdentify a possible analytic expression for the function graphed in the picture.\(y = \frac{1} {x-2}\)\(y = - \frac{1} {x-2}\)\(y = - \frac{1} {x+2}\)\(y = \frac{1} {x+2}\)