2010013707

Level: 
Project ID: 
2010013707
Source Problem: 
Accepted: 
0
Clonable: 
1
Easy: 
0
Suppose we throw an object vertically upwards at the initial speed \(v_0=60\,\mathrm{m}/\mathrm{s}\). Determine the time needed for the object to reach the maximum height and determine the corresponding maximum height as well. \[\] Hint: The vertical upwards motion of a body is the movement composed of uniformly rectilinear motion (vertically upwards) and free fall. The dependence of the instantaneous height of a body on the time is given by the relation \(h=v_0t-\frac12gt^2\), where \(v_0\) is the magnitude of the initial velocity and \(g\) is the gravitational acceleration. In this problem, calculate with the rounded value of \(g=10\,\frac{\mathrm{m}}{\mathrm{s}^2}\). We measure time \(t\) in second and height \(h\) in meters.
\(6\,\mathrm{s}\), \(180\,\mathrm{m}\)
\(6\,\mathrm{s}\), \(330\,\mathrm{m}\)
\(12\,\mathrm{s}\), \(660\,\mathrm{m}\)
\(3\,\mathrm{s}\), \(135\,\mathrm{m}\)