2010013707

Suppose we throw an object vertically upwards at the initial speed $v_0=60\mathrm{m}/\mathrm{s}$. Determine the time needed for the object to reach the maximum height and determine the corresponding maximum height as well. $$$$ Hint: The vertical upwards motion of a body is the movement composed of uniformly rectilinear motion (vertically upwards) and free fall. The dependence of the instantaneous height of a body on the time is given by the relation $h=v_{0}t-\frac{1}{2}g{t}^2$, where $v_0$ is the magnitude of the initial velocity and $g$ is the gravitational acceleration. In this problem, calculate with the rounded value of $g=10\frac{\mathrm{m}}{{\mathrm{s}}^2}$. We measure time $t$ in second and height $h$ in meters.