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Consider an object thrown upwards from the ground with the initial velocity of $30\frac{\mathrm{m}}{\mathrm{s}}$. The object moves upwards with decreasing vertical velocity until it stops. Then it starts moving vertically downwards. Find the greatest height above the ground the object does reach. $$$$ Note: The vertical distance $y$ of a thrown object is described by the equation $y=v_{0}t-\frac{1}{2}g{t}^2$, where $v_0$ is the initial velocity of the thrown object, $g$ is gravitational acceleration (count with the rounded value $10\frac{\mathrm{m}}{{\mathrm{s}}^2}$), and $t$ is the time period of the object motion in seconds.