Combinatorics

9000139701

Level: 
A
There are \(15\) athletes in an athletic meeting. Determine in how many ways it is possible to obtain the results on the first six places of the scoreboard if the place on scoreboard cannot be shared (one athlete per one place on scoreboard).
\(\frac{15!} {9!} =3\:603\:600\)
\(6^{15}=470\:184\:984\:576\)
\(15!\, 6!=941\:525\:544\:960\:000\)
\(\frac{15!} {9!\, 6!}=5\:005\)

9000139305

Level: 
A
There are five rooms with three beds and one room with five beds in a hotel. A group of \(20\) people booked rooms at this hotel. Determine the number of possible choices for the people to the five-bed room.
\(\frac{20!} {5!\; 15!}=15\:504\)
\(20\cdot 3\cdot 5=300\)
\(\frac{20!} {3!\; 5!}=3\:379\:030\:566\:912\:000\)
\(20^{5}=3\:200\:000\)

9000136903

Level: 
B
Simplify \(\left({4\above 0.0pt 0}\right) +\left ({4\above 0.0pt 1}\right) +\left ({4\above 0.0pt 2}\right) +\left ({4\above 0.0pt 3}\right) +\left ({4\above 0.0pt 4}\right)\).
\(4^{2}\)
\(14\)
\(\left({5\above 0.0pt 4}\right)\)
\(32\)
\(\left({8\above 0.0pt 4}\right)\)