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A tower is observed from two different places $A$ and $B$. The direct distance between $A$ and $B$ is $65\mathrm{m}$. If we denote the bottom of the tower by $C$, we get a triangle $ABC$ in which the measure of $\measuredangle CAB$ is ${71}^{\circ }$ and the measure of $\measuredangle ABC$ is ${34}^{\circ }$. From the point $A$ the angle of elevation of the top of the tower is ${40}^{\circ }{18}^{\prime }$. Find the height of the tower. Suppose that all $A$, $B$ and $C$ are in the same height above sea level and round your answers to nearest meters.