Level:
Project ID:
1003041602
Accepted:
1
Clonable:
0
Easy:
0
A box contains \( 50 \) transistors and \( 4 \) of them are lower quality. From all transistors \( 5 \) are selected at random for inspection. What is the probability that of lower quality is at most one of the selected transistors? Round the result to two decimal places.
\( \frac{\binom{46}5 + \binom{46}4\cdot\binom41}{\binom{50}5}\doteq 0{.}96 \)
\( \frac{\frac{46!}{41!}+\frac{46!}{42!}}{\frac{50!}{45!}}\doteq 0{.}66 \)
\( \frac{\binom{46}5 + \binom{46}4}{\binom{50}5}\doteq 0{.}72 \)
\( \frac{\frac{46!}{41!}+\frac{46!}{42!}\cdot \frac{4!}{3!}}{\frac{50!}{45!}}\doteq 0{.}71 \)