Given a right triangle \(ABC\) with the right angle at $C$ and an altitude $v$ (see the picture). Find the
valid relation between the angle \(\beta \)
and the lengths in the triangle.
Consider an isosceles triangle, i.e. the triangle with two
sides of equal length. The length of the third side is
\(4\, \mathrm{cm}\). One of the
interior angles is \(120^{\circ }\).
Find the area of this triangle.
Identify the optimal first step convenient to solve the following trigonometric
equation. Do not consider the step which is possible but does not help to solve the
equation.
\[
\sin 2x =\mathop{\mathrm{tg}}\nolimits x
\]
\(2\sin x\cdot \cos x = \frac{\sin x}
{\cos x}\)
substitution \( 2x = z\)
\(\sin x = \frac{\mathop{\mathrm{tg}}\nolimits x}
{2} \)
The parallelogram has sides of the length
\(5\, \mathrm{cm}\) and
\(4\, \mathrm{cm}\) (see the picture). The area of this
parallelogram is \(S = 10\sqrt{2}\, \mathrm{cm}^{2}\).
Find the measure of the smaller of the interior angles.
Identify the optimal first step convenient to solve the following trigonometric
equation. Do not consider the step which is possible but does not help to solve the
equation.
\[
2\cos ^{2}x =\sin x + 1
\]
Find the area of the regular octagon of the perimeter
\(16\, \mathrm{cm}\).
Round the result to two decimal places. (The regular octagon is a polygon which has
eight sides of equal length, see the picture. The perimeter of the octagon is the sum
of the length of all eight sides.)