B

2010015810

Level: 
B
The picture shows a square pyramid. The side of a base square is \(a = 10\; \mathrm{cm}\) and the height of the pyramid is \(v = 10\; \mathrm{cm}\). Find the angle \(\varphi \) between the lateral edge and the edge of the base of the pyramid.
\(\mathop{\mathrm{tg}}\nolimits {\varphi} = \sqrt5 \mathrel{\implies }\varphi \mathop{\mathop{\doteq }}\nolimits 65^{\circ }54^{\prime}\)
\(\mathop{\mathrm{tg}}\nolimits \varphi = \frac{\sqrt5} {5}\mathrel{\implies }\varphi \mathop{\mathop{\doteq }}\nolimits 24^{\circ }6^{\prime}\)
\(\mathop{\mathrm{tg}}\nolimits \frac{\varphi}{2} = \frac{\sqrt5} {5}\mathrel{\implies }\varphi \mathop{\mathop{\doteq }}\nolimits 48^{\circ }11^{\prime}\)
\(\mathop{\mathrm{tg}}\nolimits {\varphi} = \frac{\sqrt{10}} {2}\mathrel{\implies }\varphi \mathop{\mathop{\doteq }}\nolimits 57^{\circ }41^{\prime}\)

2010015809

Level: 
B
The picture shows a square pyramid \(ABCDV\). The side of a base square is \(a = 6\; \mathrm{cm}\) and the height of the pyramid is \(v = 8\; \mathrm{cm}\). Find the angle \(\varphi \) between the opposite lateral edges (the angle \(AVC\)).
\(\mathop{\mathrm{tg}}\nolimits \frac{\varphi}2 = \frac{3\sqrt2} {8}\mathrel{\implies }\varphi \mathop{\mathop{\doteq }}\nolimits 55^{\circ }53'\)
\(\mathop{\mathrm{tg}}\nolimits \varphi = \frac{3\sqrt2} {8}\mathrel{\implies }\varphi \mathop{\mathop{\doteq }}\nolimits 27^{\circ }56^{\prime}\)
\(\mathop{\mathrm{tg}}\nolimits \frac{\varphi}{2} = \frac{3} {8}\mathrel{\implies }\varphi \mathop{\mathop{\doteq }}\nolimits 41^{\circ }7^{\prime}\)
\(\mathop{\mathrm{tg}}\nolimits \frac{\varphi}2 = \frac{8} {3\sqrt2}\mathrel{\implies }\varphi \mathop{\mathop{\doteq }}\nolimits 124^{\circ }7^{\prime}\)

2010015808

Level: 
B
The picture shows a square pyramid. The side of a base square is \(a = 6\; \mathrm{cm}\) and the height of the pyramid is \(v = 10\; \mathrm{cm}\). Find the angle \(\varphi \).
\(\mathop{\mathrm{tg}}\nolimits \varphi = \frac{10} {3\sqrt2}\mathrel{\implies }\varphi \mathop{\mathop{\doteq }}\nolimits 67^{\circ }\)
\(\mathop{\mathrm{tg}}\nolimits \varphi = \frac{10} {3}\mathrel{\implies }\varphi \mathop{\mathop{\doteq }}\nolimits 73^{\circ }18^{\prime}\)
\(\mathop{\mathrm{tg}}\nolimits \frac{\varphi}{2} = \frac{3\sqrt2} {10}\mathrel{\implies }\varphi \mathop{\mathop{\doteq }}\nolimits 45^{\circ }59^{\prime}\)
\(\mathop{\mathrm{tg}}\nolimits \frac{\varphi}2 = \frac{3} {10}\mathrel{\implies }\varphi \mathop{\mathop{\doteq }}\nolimits 33^{\circ }24^{\prime}\)

2010015804

Level: 
B
The base \( ABCD \) of a square pyramid \( ABCDV \) has an edge of \( 6\,\mathrm{cm} \). The height of the pyramid is \( 3\sqrt2\,\mathrm{cm} \). Find the distance between the point \( A \) and the line \( CV \) (see the picture).
\( 6\,\mathrm{cm} \)
\( 3\sqrt{3}\,\mathrm{cm} \)
\( 9\,\mathrm{cm} \)
\( 3\sqrt{2}\,\mathrm{cm} \)

2010015604

Level: 
B
The base \( ABCD \) of a square pyramid \( ABCDV \) has an edge of \( 4\,\mathrm{cm} \). The height of the pyramid is \( 6\,\mathrm{cm} \). Find the distance between the point \( A \) and the point \( S_{VB} \), where \( S_{VB} \) is the midpoint of the edge \( VB \).
\( \sqrt{19}\,\mathrm{cm} \)
\( \sqrt{35}\,\mathrm{cm} \)
\( 3\sqrt{3}\,\mathrm{cm} \)
\( \sqrt{5}\,\mathrm{cm} \)