Logarithmic functions | math4u.vsb.cz

1103099809

Level:

A

Below, we are given the graph of the logarithmic function

f (x) = \log_{4} (x - 3)

. Use the graph of

f

as help to identify which of the next four given graphs is the graph of

g (x) = \log_{4} (3 - x)

.

1103099808

Level:

A

Below, we are given the graph of the logarithmic function

f (x) = \log (x)

. Use the graph of

f

as help to identify which of the next four given graphs is the graph of

g (x) = - 4 \log (x)

.

1103099807

Level:

A

Below, we are given the graph of the logarithmic function

f (x) = \log_{\frac{1}{3}} x

. Use the graph of

f

as help to identify which of the next four given graphs is the graph of

g (x) = \log_{\frac{1}{3}} (x - 2)

.

1103099806

Level:

A

Below, we are given the graph of the logarithmic function

f (x) = \log_{7} x

. Use the graph of

f

as help to identify which of the next four given graphs is the graph of

g (x) = \log_{7} x + 2

.

1103099805

Level:

A

Below, we are given the graph of the logarithmic function

f (x) = \log_{3} x

. Use the graph of

f

as help to identify which of the next four given graphs is the graph of

g (x) = \log_{3} x - 2

.

1003099804

Level:

A

Which of the following equations is the equation of the vertical asymptote of

f (x) = \log_{3} (x + 5)

?

x = - 5

x = 5

y = 5

y = - 5

1003099803

Level:

A

Find the vertical asymptote of

f (x) = \log_{\frac{1}{3}} (x - 2)

.

x = 2

x = - 2

y = 2

y = - 2

1103099802

Level:

A

The function

f (x) = \log_{\frac{1}{2}} (x + 3)

is graphed below. Which of the following equations is the equation of the vertical asymptote of

f

?

x = - 3

x = 3

y = - 3

y = 3

1103099801

Level:

A

The function

f (x) = \log_{2} (x + 3)

is graphed below. Find the vertical asymptote of

f

.

x = - 3

x = 3

y = - 3

y = 3

1003101103

Level:

C

Find the true statement about the function

f (x) = \log_{2} | x |

.

The function

f

is even.

The function

f

has the minimum at

x = 0

.

The function

f

is bounded.

The function

f

is increasing.