1003020412 Level: BA parabola passes through the points \( K=[0;0] \) and \( L=[6;-2] \) and it is symmetric with respect to \( y \)-axis. What are the coordinates of its vertex?\( [0;0] \)\( [6;-2] \)\( [3;0] \)\( [-6;-2] \)\( [0;-1] \)
1003020413 Level: BThe equation of a parabola is given by \( x^2+6x+y+10=0 \). What are the coordinates of its vertex?\( [-3;-1] \)\( [3;1] \)\( [3;-1] \)\( [-1;-3] \)\( [-1;3] \)
1003024001 Level: BThe equation of a hyperbola is given by \( 4x^2-y^2-12=0 \). Which of the following points lies on such hyperbola?\( [-2;2] \)\( [2;1] \)\( [0;12] \)\( [3;0] \)\( [\sqrt3;12] \)
1003024003 Level: BLet \( A=[0;0] \), \( B=[1;7] \), \( C=[-1;-5] \) be points that all lie on a parabola. Find the equation of the parabola.\( y=x^2+6x \)\( y=x^2 \)\( y=7x^2 \)\( y=-x^2+4x \)\( x=y^2 \)
1003024004 Level: BDecide whether the equation \( 4x^2+9y^2-8x+18y+13=0 \) (in \( x \)-\( y \) plane) describes:a pointan ellipsea parabolaa hyperbolaan empty set
1003024005 Level: BDecide whether the equation \( 4x^2+4y-8x=1\) (in \( x \)-\( y \) plane) describes:a parabolaan ellipsea circlea hyperbolapoint \( \left[0;\frac14\right] \)
1003024006 Level: BDecide whether the equation \( (x+3)^2+(y+4)^2=5 \) (in \( x \)-\( y \) plane) describes:a circle with center \( [-3;-4] \)a circle with center \( [3;4] \)point \( [-3;-4] \)a hyperbolaan ellipse with center \( [3;4] \)
1003024007 Level: BDecide whether the equation \( 2x^2-4y^2-6x-12y=0 \) (in \( x \)-\( y \) plane) describes:a hyperbolaa circlea parabolaan ellipsepoint \( \left[\frac32;\frac{-3}2\right] \)
1003024008 Level: BDecide which of the given equations describes a hyperbola.\( 4x^2-9y^2+18y-45=0 \)\( 4x^2+9y^2-8x-36y+4=0 \)\( x^2+y^2-2x+4y-4=0 \)\( x^2+y^2-12x+40=0 \)\( x^2-2x-4y+1=0 \)
1003024101 Level: BThe equation of a hyperbola with the center \( S=[-1;3] \), the focus \( F=[4;3] \), and the vertex \( A=[2;3] \) is given by:\( \frac{(x+1)^2}{9}-\frac{(y-3)^2}{16} =1 \)\( \frac{(x-1)^2}{9}-\frac{(y+3)^2}{16} =1 \)\( \frac{(x+1)^2}{9}+\frac{(y-3)^2}{16} =1 \)\( \frac{(x-1)^2}{16}-\frac{(y+3)^2}{9} =1 \)\( \frac{(y-3)^2}{16}-\frac{(x+1)^2}{9} =1 \)