1003024101 | math4u.vsb.cz

Subtema:

Parte:

Project ID:

1003024101

Source Problem:

Accepted:

1

Clonable:

1

Easy:

0

Elige la ecuación de la hipérbola con centro

S = (- 1; 3)

, foco

F = (4; 3)

y vértice

A = (2; 3)

:

\frac{(x + 1)^{2}}{9} - \frac{(y - 3)^{2}}{16} = 1

\frac{(x - 1)^{2}}{9} - \frac{(y + 3)^{2}}{16} = 1

\frac{(x + 1)^{2}}{9} + \frac{(y - 3)^{2}}{16} = 1

\frac{(x - 1)^{2}}{16} - \frac{(y + 3)^{2}}{9} = 1

\frac{(y - 3)^{2}}{16} - \frac{(x + 1)^{2}}{9} = 1