SubArea: ConicsLevel: BProject ID: 1003024101Source Problem: 2010006306Accepted: 1Clonable: 1Easy: 0The equation of a hyperbola with the center S=[−1;3], the focus F=[4;3], and the vertex A=[2;3] is given by:(x+1)29−(y−3)216=1(x−1)29−(y+3)216=1(x+1)29+(y−3)216=1(x−1)216−(y+3)29=1(y−3)216−(x+1)29=1