1003024101

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Project ID: 
1003024101
Source Problem: 
Accepted: 
1
Clonable: 
1
Easy: 
0
The equation of a hyperbola with the center S=[1;3], the focus F=[4;3], and the vertex A=[2;3] is given by:
(x+1)29(y3)216=1
(x1)29(y+3)216=1
(x+1)29+(y3)216=1
(x1)216(y+3)29=1
(y3)216(x+1)29=1