Determine the set of all values of the parameter \( a \in \mathbb{R} \setminus \{0\}\) for which the given equation has no solution.
\[
\frac{x-1}{x} = \frac{2-a}{3a}
\]
The system of equations is given by:
\[\begin{aligned}
2 x-y +z=5 & &
\\x +2y-3z =17& &
\\x +y -2z= 12& &
\end{aligned}\]
When solving the system using Cramer's rule, we evaluate determinants of four matrices. What is the sum of all these determinants?
The system of equations is given by:
\[\begin{aligned}
x+y -z=3 & &
\\3x -y-7z =-7& &
\\ax +3y +z= 11& &
\end{aligned}\]
Find the value of a real parameter \(a\) for which the system has infinitely many solutions.
The system of equations is given by:
\[\begin{aligned}
x-2y +3z= 2 & &
\\ax +y =5& &
\\-2x +6y -2z= 4& &
\end{aligned}\]
Find the value of a real parameter \(a\) for which the system has no solution.
The system of equations is given by:
\[\begin{aligned}
x+2z= 3 & &
\\2x -y+ z = 2& &
\\3x -2 y -z= 1 & &
\end{aligned}\]
When solving the system using Cramer's rule, we evaluate determinants of four matrices. What is the arithmetic mean of all these determinants?
The coefficient matrix of a system of three linear equations with three unknowns is:
\[
\left (\array{
1& 2& 1\cr
3& -5& 2\cr
1& 0& -3} \right ).~
\]
What is the column of the right sides if the solution is the ordered triple \([−7; 2;−1]\)?
To solve the system of three linear equations with three unknowns, it is necessary to calculate the determinants of the matrices:
\[
\left (\array{
1& -2& 3\cr
2& 1& -7\cr
-3& 1& -5} \right ),~
\left (\array{
1& 3& -1\cr
2& -7& -3\cr
-3& -5& 1} \right ).
\]
Which of the given ordered triples is the solution to this system?