1003085706 Level: AThe sum of all \( \theta \), where \( 0^{\circ} < \theta < 360^{\circ} \), satisfying the equation \( \sin\!\left(\theta + 10^{\circ}\right) = 0.5 \) is:\( 160^{\circ} \)\( 140^{\circ} \)\( 300^{\circ} \)\( 200^{\circ} \)
1003085705 Level: ASolving the equation \( 2\sin\!\left(x + \frac{\pi}4 \right) = \sqrt3 \) for \( x \), where \( x\in (0; \pi) \), you get:\( x\in\left\{ \frac{\pi}{12};\frac{5\pi}{12} \right\} \)\( x\in\left\{ \frac{\pi}{12} \right\} \)\( x\in\left\{ \frac{3\pi}{12};\frac{5\pi}{12} \right\} \)\( x\in\left\{ \frac{13\pi}{12};\frac{5\pi}{12} \right\} \)
1003085704 Level: AThe solution set of the equation \( \cos\!\left(2x - \frac{\pi}3 \right) = - 0.5 \), where \( 0 < x < 2\pi \), is:\( \left\{ \frac{\pi}2; \frac{3\pi}2; \frac{5\pi}6; \frac{11\pi}6 \right\} \)\( \left\{ \frac{\pi}2; \frac{3\pi}2 \right\} \)\( \left\{ \frac{5\pi}6; \frac{11\pi}6 \right\} \)\( \left\{ \frac{3\pi}2; \frac{5\pi}6; \frac{11\pi}6; \pi \right\} \)
1003085703 Level: AThe solution set of the equation \( 2\sin\!\left(x - \frac{\pi}6 \right) = 1 \), where \( x\in[0; \pi] \), is:\( \left\{\frac{\pi}3; \pi \right\} \)\( \left\{\frac{\pi}6 \right\} \)\( \left\{\frac{\pi}3 \right\} \)\( \left\{\frac{\pi}6; \frac{\pi}2 \right\} \)
1003085702 Level: ASolve \( 2\sin^2x = \sqrt2 \sin x \) for \( x \), where \( x\in\mathbb{R} \).\( x\in\bigcup\limits_{k\in\mathbb{Z}}\left[ \{k\pi\}\cup\left\{ \frac{\pi}4+2k\pi \right\}\cup\left\{ \frac{3\pi}4+2k\pi\right\} \right] \)\( x\in\bigcup\limits_{k\in\mathbb{Z}}\left[ \left\{ \frac{\pi}4+2k\pi \right\}\cup\left\{ \frac{3\pi}4+2k\pi\right\} \right] \)\( x\in\bigcup\limits_{k\in\mathbb{Z}}\left[ \left\{ \frac{\pi}4+k\pi \right\}\cup\left\{ \frac{3\pi}4+k\pi\right\} \right] \)\( x\in\bigcup\limits_{k\in\mathbb{Z}}\left[ \{2k\pi\}\cup\left\{ \frac{\pi}4+k\pi \right\}\cup\left\{ \frac{3\pi}4+k\pi\right\} \right] \)
1003085701 Level: AFind all \( x \), \( x\in\mathbb{R} \), such that \( \mathrm{cotg}^2x = - \mathrm{cotg}\,x \).\( x\in\bigcup\limits_{k\in\mathbb{Z}}\left[ \left\{\frac{3\pi}4+k\pi \right\}\cup\left\{\frac{\pi}2+k\pi \right\} \right] \)\( x\in\bigcup\limits_{k\in\mathbb{Z}}\left\{\frac{3\pi}4+2k\pi \right\} \)\( x\in\bigcup\limits_{k\in\mathbb{Z}}\left\{\frac{3\pi}4+k\pi \right\} \)\( x\in\bigcup\limits_{k\in\mathbb{Z}}\left\{\frac{\pi}2+k\pi \right\} \)
1003099509 Level: AGiven the numbers \( x = 4+2\sqrt5 \) and \( y=6-2\sqrt5 \), the fraction \( \frac xy \) can be written in the form:\( \frac{11+5\sqrt5}4 \)\( \frac{7\sqrt5-9}4 \)\( \frac{-5\sqrt5}2 \)\( 8\sqrt5 \)
1003099508 Level: AEvaluate the expression \( \frac{2-x}{x-2} \) for \( x=2-\sqrt2 \).\( -1 \)\( \sqrt2 - 2 \)\( 2 - \sqrt2 \)\( 1 \)
1003099505 Level: ARewrite \( \frac{2-\sqrt3}{2+\sqrt3} \) by rationalizing the denominator.\( 7-4\sqrt3 \)\( \left(2-\sqrt3\right)\left(2+\sqrt3\right) \)\( \frac{7-4\sqrt3}5 \)\( \frac{7-4\sqrt3}7 \)
1003099504 Level: ARationalizing the denominator \( \frac1{\sqrt5+\sqrt7} \) we get:\( \frac{\sqrt7-\sqrt5}2 \)\( \frac{\sqrt5+\sqrt7}2 \)\( \frac{\sqrt5-\sqrt7}2 \)\( \frac{-\sqrt7-\sqrt5}2 \)