Radical equations and inequalities

9000023803

Level: 
A
In the following list identify a true statement referring to the solution of the following equation. \[ \sqrt{x + 3} = 3 + x \]
The difference of the bigger and smaller solutions is \(1\).
The difference of the bigger and smaller solutions is \(- 1\).
The difference of the smaller and the bigger solutions is \(1\).
The difference of the smaller and twice the bigger solutions is \(- 1\).

9000023804

Level: 
A
Identify a true statement which concerns to the following equation. \[ \sqrt{x + 3} = x - 3 \]
The solution is in the interval \((5;8)\).
The solution is in the interval \([ - 2;2] \).
The solution is in the interval \([ - 3;1)\).
The solution is in the interval \([ 3;5)\).

9000023805

Level: 
A
Identify a true statement about the following equation. \[ \sqrt{6 + x} = -x \]
The solution is in the set \(\left \{x\in \mathbb{R} : -4 < x\leq - 1\right \}\).
The solution is in the set \(\left \{x\in \mathbb{R} : 1\leq x\leq 5\right \}\).
The solution is in the set \(\left \{x\in \mathbb{R} : -6\leq x\leq - 3\right \}\).
The solution is in the set \(\left \{x\in \mathbb{R} : -2 < x < 3\right \}\).

9000023809

Level: 
A
Identify a true statement which concerns to the following equation. \[ \sqrt{16 - 5x} = 2 - x \]
The solution \(x\) satisfies \(|x| > 3\).
The solution \(x\) satisfies \(|x| < 3\).
The solution \(x\) satisfies \(|x + 1| < 3\).
The solution \(x\) satisfies \(|x + 1| > 3\).

9000023810

Level: 
A
Denote by \(x_{1}\) the solution of the equation \[ \sqrt{6 - 2x} = -x - 1 \] and by \(x_{2}\) the solution of the equation \[ \sqrt{2x + 6} = 9 - x. \] Identify a correct statement about \(x_{1}\) and \(x_{2}\).
\(|x_{1}| = |x_{2}|\)
\(|x_{1}| < |x_{2}|\)
\(|x_{1}| > |x_{2}|\)
\(5|x_{1}| = |x_{2}|\)