Analytical Space Geometry

9000101001

Level: 
A
Determine whether two lines $p$ and $q$ are identical, parallel, intersecting or skew. \[\begin{aligned} p\colon x & = 1 + t, & & \\y & = 2 - t, & & \\z & = 1 - t,\ t\in \mathbb{R} & & \end{aligned}\] \[\begin{aligned} q\colon x & = 2s, & & \\y & = -1, & & \\z & = 2 - 2s,\ s\in \mathbb{R} & & \end{aligned}\]
intersecting lines
skew lines
identical lines
parallel lines, not identical

9000101108

Level: 
B
Find the distance between the line \(q\) and the plane \(\beta \). \[ \beta \colon x+4y+2z-4 = 0,\qquad \qquad \begin{aligned}[t] q\colon x& = 4, & \\y & = -2t, \\z & = 1 + 4t,\ t\in \mathbb{R} \\ \end{aligned} \]
\(\frac{2} {\sqrt{21}}\)
\(\frac{4} {\sqrt{21}}\)
\(0\)
\(1\)

9000101002

Level: 
A
Find the intersection of the line \(AB\) and the line \(p\), where \(A = [0,1,2]\), \(B = [4,1,-2]\) and \[ \begin{aligned}p\colon x& = 1 + t, & \\y & = 2 - t, \\z & = 1 - t,\ t\in \mathbb{R}. \\ \end{aligned} \]
\([2,1,0]\)
\([1,2,1]\)
\([3,0,-1]\)
There is no intersection.

9000101003

Level: 
A
Find the value of the real parameter \(m\in \mathbb{R}\) which ensures that the lines \(p\) and \(q\) are parallel and not identical. \[ \begin{aligned}p\colon x& = 1 + t, & \\y & = 2 - t, \\z & = 1 - t,\ t\in \mathbb{R} \\ \end{aligned}\qquad \qquad \begin{aligned}q\colon x& = s, & \\y & = -s, \\z & = 3 + ms,\ s\in \mathbb{R}. \\ \end{aligned} \]
\(m = -1\)
\(m = -2\)
\(m = 0\)
\(m = 1\)

9000101004

Level: 
A
Find all the values of the real parameter \(m\) so that the lines \(p\) and \(q\) are skew lines. \[ \begin{aligned}p\colon x& = 1 + t, & \\y & = 2 - t, \\z & = 1 - t,\ t\in \mathbb{R} \\ \end{aligned}\qquad \qquad \begin{aligned}q\colon x& = s, & \\y & = 1 + s, \\z & = 3 + ms,\ s\in \mathbb{R} \\ \end{aligned} \]
\(m\in\mathbb{R}\setminus\{-2\}\)
No solution exists.
The lines are skew for every real \(m\).
\(m = -2\)

9000101005

Level: 
A
Find the value of the real parameter \(m\) which ensures that the lines \(p\) and \(q\) are intersecting lines (with a unique common point). \[ \begin{aligned}p\colon x& = 1 + t, & \\y & = 2 - t, \\z & = 1 - t,\ t\in \mathbb{R} \\ \end{aligned}\qquad \qquad \begin{aligned}q\colon x& = s, & \\y & = 1 + s, \\z & = 3 + ms,\ s\in \mathbb{R} \\ \end{aligned} \]
\(m = -2\)
No solution exists.
The lines are intersecting for every real \(m\).
\(m = 2\)